Find the probability in a group of 10 students sitting in a row , two of them
always sit next to each other

• Assume that these 2 students are 1 and then u can sit is 9! and these 2 students can sit by 2 ways then total ways are 9!*2
  and the probability is 9!*2/10! = 1/5=0.2
• 12 years agoHelpfull: Yes(18) No(2)
• permutation is 2!9!(n(E))
  n(s)= 10!
  probability = (2!9!)/10! = 0.2
• 10 years agoHelpfull: Yes(6) No(0)
• 2!*9!/10!
  =1/5
  
• 10 years agoHelpfull: Yes(2) No(0)
• 2!9!
  taking 2 students as 1 we have 9 arrangements.. and those 2 can exchange positions within themselves.
• 10 years agoHelpfull: Yes(0) No(4)