a men walked 30m west 5m south 10m west 35m north to tollgate find the distance from the start gate?

• Ans. 50m
  The man is toward West = 30+10 = 40m
  The man is towards North = 35m(N) - 5m(S) = 30m
  Therefore, the distance from the start gate = sqrt(40^2+30^2)
  = sqrt(2500) = 50m
• 12 years agoHelpfull: Yes(28) No(8)
• Draw a fig as given in question. Its a rightangle triangle with 30m and 40 m side then the distance is 50 m.
• 12 years agoHelpfull: Yes(7) No(0)
• 50 m north west because its became a right triangle of 30m and 40m so the hypotanus became 50m
• 12 years agoHelpfull: Yes(5) No(0)
• 
  N
  |
  WE
  |
  s
  30m west
  | |------.
  35m n| | 5m south
  |------------
  10m west
  
  clearly the distance is 30 + 10 = 40 is the ans only...why there is a square root stuffs all in the below answer ?....he did not travel to any NE or SE to calculate them also...its perfect south and north and distance is 40 and its the ans!!
• 12 years agoHelpfull: Yes(3) No(10)
• Directed distance from the start gate is = 50m
  [30(w)+10(W)]= 40m
  [35(N)-5(S)] = 30m
  therefore , sqrt of (1600+900) = 50m
• 12 years agoHelpfull: Yes(3) No(0)
• N
  W E
  S
  '
  35M
• 12 years agoHelpfull: Yes(2) No(2)
• 35m from starting position
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• base= 40m (30+10)
  perpendicular= 30m (35-5)
  since the formation is right angled so u need to find hypotenuse, thus answer is (1600+900)^(1/2) = 50
  ans) 50m north west
• 10 years agoHelpfull: Yes(1) No(0)
• 40m from east
• 10 years agoHelpfull: Yes(1) No(1)
• 
  
  ---------
• 12 years agoHelpfull: Yes(0) No(3)
• ^
  |
  |
  35m north |
  | 30m west
  |--------
• 12 years agoHelpfull: Yes(0) No(5)