A and B can do a piece of work in 40 days. thier skills of doing the work are in the ratio 8:5. how many days will A take to engage alone ??

• Ratio of efficiency of A:B=8:5
  Total Efficiency=13
  When the total efficiency is 13, they complete the work in 40 days
  When the efficiency of A is 8, A could complete the work in (40/8)*13=65 days
  Thus. A alone can do the work in 65 days
• 11 years agoHelpfull: Yes(25) No(3)
• Ratio of work done by A & B=8:5
  Ratio of time taken by A & B=5:8i.e.,
  if A takes 5x days to complete the work (A 1day work=1/5x)
  then
  B takes 8x days to complete the work (B 1day work=1/8x)
  1/5x+1/8x=1/40
  13x/40=1/40
  x=13
  from this A=5*13=65
  so answer is 65
• 11 years agoHelpfull: Yes(12) No(1)
• A+B can do a work in 40 days,so (A+B)'s one day work is 1/40.
  (A's 1day work):(B's 1 day work)=8:5.hence divide this 1/40 in the ratio of 8:5.
  hence A can do the work in 1/40 *(8/13)=1/65.
• 11 years agoHelpfull: Yes(5) No(0)
• one day work for a and b is 1/40
  so a's one day work is 1/40*8/13
  =1/65
  so a will done the job in 65 days
  
• 8 years agoHelpfull: Yes(2) No(0)
• Total work=(8+5)*40
  =520
  efficiency of A=8
  Hence ,
  work will be done by A in 520/8=65 Days
  
  Ans-65
• 7 years agoHelpfull: Yes(0) No(0)
• 40/8*13=65
  
• 7 years agoHelpfull: Yes(0) No(0)
• Here, Total work =40x(8+5)=40x13
  Required No. of Days=40x13/8=65Ans.
• 5 years agoHelpfull: Yes(0) No(0)
• total work =40*13
  time=work/efficiency =40*13/8 =65
• 4 years agoHelpfull: Yes(0) No(0)
• Given ratio of efficiency of x:y=8:5
  total efficiency=13
  and complete work in 40 days
  x is 8 and complete work in (40/8)*13=65 days
• 4 years agoHelpfull: Yes(0) No(0)
• A B
  8 : 5
  A= (total days *sum of ratio)/asked value
  A=(40*13)/8=65
• 4 years agoHelpfull: Yes(0) No(0)