Latest Infosys Aptitude Question SOLUTION: Three neighbors are there. 1st one lends 2nd and 3rd that many no. of tractors that then already each had. After few months, 2nd lends to 1st and 3rd that many tractors then they

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(#M40000001) INFOSYS Logical Reasoning question Keep an EYE

Three neighbors are there. 1st one lends 2nd and 3rd that many no. of tractors that then already each had. After few months, 2nd lends to 1st and 3rd that many tractors then they had. After a few months 3rd lends to 1st and 2nd that many tractors then they had. Now each of them got 24. Find how many they had initially?

Asked In Infosys (14 years ago)

Solved Tijo Jose Read Solution (13)

Is this Puzzle helpful?   (135)   (42) Submit Your Solution General Mental Ability

Read Solution (13) :

Harjinder Singh  (10 years ago)

Try solving from the end
1st 2nd 3rd
24 24 24 (last)
12 12 48 (before 3rd lend to 1st and 2nd as many as they had
6 42 12 (before 2nd's transaction
39 21 12 (before 1st's transaction)

Is this solution Helpfull? Yes (42) | No (9)  

sree  (10 years ago)

here is a short cut fr this prob
no. of neighbors =3
no.of tractors left with each of them=24
now 24/2^3=24/8=3
now 13*3 7*3 4*3=39 21 12
same is da case for any question of dis type.jus divide the number left by 2 power transactions.multiply it with 13,7 and 4 which gives u final result

Is this solution Helpfull? Yes (28) | No (9)  

Pooja Sharma  (9 years ago)

1st lends y tractors to 2nd and z tractors to 3rd.
So now no of Tractors:
1st: x-(y+z)
2nd: 2y
3rd: 2z

2nd lends x-(y+z) tractors to 1st and 2z tractors to 3rd.
So now no of Tractors:
1st: 2x-2y-2z
2nd: 2y-(x-y+z)
3rd: 4z

3rd lends 2x-2y-2z tractors to 1st and 2y-(x-y+z) tractors to 2nd.
So now no of Tractors:
1st: 4x-4y-4z
2nd: 6y-2x-2z
3rd: 4z -(x+y-3z)
4x-4y-4z = 24
or, x-y-z = 6 ..........(i)
6y-2x-2z = 24
or -x+3y-z = 12 ....(ii)
-x-y+7z = 24 .........(iii)

Solving (i) (ii) and (iii)
x = 39, y = 21, z = 12
1ST HAD 39
2ND HAD 21
3RD HAD 12

Is this solution Helpfull? Yes (23) | No (7)  

Tijo Jose  (14 years ago)

1ST HAD 39
2ND HAD 21
3RD HAD 12

Is this solution Helpfull? Yes (17) | No (13)  

Sanal Jose  (14 years ago)

39, 21 and 12 tractors each in order for 1st, 2nd and 3rd neighbours

Is this solution Helpfull? Yes (10) | No (10)  

Chirag Ranjan Lahiri  (9 years ago)

39, 21 and 12 tractors

Is this solution Helpfull? Yes (9) | No (4)  

SREEDHAR  (9 years ago)

from the the last step
24 24 24 (after 3rd step)
12 12 48 (after 2nd step)
6 42 24 (after 1st step)
39 21 12 (initially)

Is this solution Helpfull? Yes (8) | No (3)  

Deepika  (9 years ago)

we can easily solve this from end
1st 2nd 3rd
24 24 24 (finally they got) (3rd has 48,after lends to 1st and 2nd how much they had i.e., 12 and 12 then 48-24=24)
12 12 48 (before 3rd lends to 2nd and 3rd )(2nd has 42,after lends to 1st and 3rd i.e 6 and 24 then 42-(6+24)=12)
6 42 24 (before 2nd)(1st has 39,after lends to 2nd and 3rd i.e 21 and 12 then 39-(21+12)= 6)
39 21 12 (before 1st)

Is this solution Helpfull? Yes (7) | No   

Vijesh Jain  (11 years ago)

Please explain,,,, how did u all get this answer!!

Is this solution Helpfull? Yes (4) | No   

krishan kumar  (9 years ago)

pooja we dont have a full day to give the test .... harjinders ans is perfect

Is this solution Helpfull? Yes (1) | No   

yashodhara  (9 years ago)

best solution done by deepika..(y)

Is this solution Helpfull? Yes | No   

harshavi  (9 years ago)

we would get the solution by the equations 4x-4y-4z=24
-2x+6y-2z=24
-x-y+7z=24
we will get x=39,y=21,z=12

Is this solution Helpfull? Yes | No   

d.avi  (8 years ago)

13*3=39,
7*3=21,
4*3=12

Is this solution Helpfull? Yes | No   

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