Due to less participation, we are shutting down the today's puzzle section from 1st Nov 2022. We are working on it's new format and will update you once it launch.
Today's Puzzle Solve today's Puzzle and be among the top 5
We are excited to announce our new prize rules which are more rewarding and more inclusive!
We are also introducing a new monthly winner award for the Top Scorer of the month! Effective from Jan 2019View New Prize Rule
Get a new puzzle every day at 11:00:00 AM (IST) sharp from MONDAY to FRIDAY.
Advertisements
Previous Day Puzzle and users best solution .
28 Oct 2022 : Pipes & Cisterns
Pipes A and B are fitted to a tank. A can fill the tank in 1½ hours and capacity of B which is emptying pipe is half that of A. If B is fitted at one-third of the height of the tank from the base and both the pipes are opened simultaneously, then time taken to fill the empty tank is:
Filling capacity of A per hour = 2/3, .'. Emptying capacity of B per hour = (1/2)*(2/3) = 1/3
As B, the emptying pipe is fitted at 1/3 of the height of the tank from base, so the draining will start only after tank is 1/3 full.
Now time taken to fill 1/3 tank by A = (1/3)/(2/3) = 1/2 hrs.
Effective filling per hour after 1/3 tank is full = 2/3 - 1/3 = 1/3
.'. Time required to fill remaining 2/3 tank = (2/3) / (1/3) = 2 hrs
Total time = (1/2 + 2) Hrs = 2 hours 30 minutes
Correct Option 8)
Language is remarkable, except under the extreme constraints of mathematics and logic, it never can talk only about what it's supposed to talk about but is always spreading around.