Latest TCS Aptitude Question SOLUTION: Park, Jack, and Galvin distributed prize money of x dollars among themselves. Park received 3/10 of what Jack and Galvin together received.Jack received 3/11 of what Park and Galvi

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Park, Jack, and Galvin distributed prize money of x dollars among themselves. Park received 3/10 of what Jack and Galvin together received.Jack received 3/11 of what Park and Galvin together received. What is the ratio of the amount received by Park to the amount received by Jack?
(A)7 : 8
(B)8 : 7
(C)10 : 11
(D)14 : 13
(E)77 : 80

Asked In TCS ATWAL (11 years ago)

Unsolved Read Solution (3)

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chandu161  (11 years ago)

only 2 equations
P = Park ,J = Jack, G = Galvin;
P = 3/10(J+G)-----1
J = 3/11(P+G) ----2

from 1 we can write

G = (10p/3) - J ---3

substitute 3 in 2 making all P and J Terms in the equation.

J = 3/11(P + (10p/3) - J)

solve it

we get P/J = 14/13

thats it!!

Is this solution Helpfull? Yes (14) | No (1)  

chaitanya  (11 years ago)

Let the amounts received by Park, Jack and Galvin be
P,J, and G respectively.

Since the prize money, x was distributed to Park, Jack, and Galvin, the amount that Jack and Galvin together received equals
x–(the amount received by Park) = 120 –P.

Since we are given that Park received 3/10 of what Jack and Galvin together received,
we have the equation
P= (3/10)(x–P)

Solving the equation for P yields
P= 3x/13

Similarly, since we are given that Jack received 3/11of what Park and Galvin together received (x–J),
wehave the equation
J= (3/11)(x–J)

Solving the equation yields
J= 3x/14

Now
P:J = 3x/13 : 3x/14 = 14 : 13

The answer is (D).

Is this solution Helpfull? Yes (9) | No   

Yuvaraj  (11 years ago)

According to 1st statement
Park=1/3(Jack+Galvin)
=> Galvin=3Park-Jack

According to 2nd statement
Jack=3/11(Park+Galvin)
=> Galvin=(11/3)Jack-Park


So we get
3Park-Jack=(11/3)Jack-Park
12Park=14Jack
Park/Jack=7/6

Park:Jack=7:6

Is this solution Helpfull? Yes (2) | No (9)  

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