Latest campus Aptitude Question SOLUTION: Q. The last digit of number is same as the last digit of its square. How many such a number exists from 0 to 90.

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Q. The last digit of number is same as the last digit of its square. How many such a number exists from 0 to 90.

Asked In campus vishnu (11 years ago)

Solved jomon v j Read Solution (4)

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jomon v j  (11 years ago)

Answer 37

the only digits with square ending in same digits are 1,5,6,10

therefore such numbers in one of these digits

for eg 11,15,16,20 4 numbers between 11 to 20

total numbers =9*4+1 (square of zero =0)=37

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PRATIK JAISWAL  (11 years ago)

ans=26... the numbers are 1,6,10,11,16,20,21,26,30,31.......86 (we will not take 90 because we are aked to write number between 0-90 )

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Rupal Sharma  (10 years ago)

its 36,

such numbers are 1,5,6 and 10
so 1,11,21,31,41,51,61,71,81
same with 5,6 and 10
9*4=36

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avinash shashikant sindkar  (10 years ago)

answer is 37
we have to find the last digit is same as the last digit of its square.
so in 0 to 9 there are 4 numbers 0,1,5,6 whose last digit is same as square of that digit.
so 10 to 19 there are also 4 no.
like that 9*4=36 for 0 to 89
and 90 also=1
so total no will be 37

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