Latest TCS Aptitude Question SOLUTION: The size of program is N.And the memory occupied by the program is given by M=square root of 100N.If the size of the program is increased by 1% then how much more memory is require

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The size of program is N.And the memory occupied by the program is given by M=square root of 100N.If the size of the program is increased by 1% then how much more memory is required now?
a.1.0%
b.2.6%
c.0.5%
d.1.4%

Asked In TCS vanithamateti (11 years ago)

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Mohit Dhiman  (11 years ago)

Initially size=N, memory=100N
size increased by 1%, means new size=1.01N, new memory=100*1.01N=101N
Percentage increase in memory=1%
Ans= 1%

Is this solution Helpfull? Yes (14) | No (3)  

Neel Mani Singh  (11 years ago)

size memory(M)
n (100n)^0.5=10sqrt(n)
1.01n 10sqrt(1.01n)=1.0049*10sqrt(n)=1.005M
difference in memory=0.005M
%increase in memory=(0.005M/M)*100=0.5%

Is this solution Helpfull? Yes (10) | No (1)  

Rishabh Goel  (11 years ago)

abe gadho saab galat ho tum iska answer 0.5 hai

Is this solution Helpfull? Yes (6) | No (11)  

hari  (11 years ago)

when program size=N;
Memory M=(100N)^(1/2); //square root of 100N from Question
size of increase 1%, M=(100*1.1)^(1/2) = (110)^(1/2);
(100)^(1/2)=10;//at N Memory
(100*1.1)^(1/2)=10.4; //at N=1% increase
required Memory increase = 4% (note-none of the options is correct)

Is this solution Helpfull? Yes (3) | No (5)  

bhavatarini  (11 years ago)

CAN ANY ONE EXPLAIN IT PLZ?!

Is this solution Helpfull? Yes (1) | No (7)  

Arvind kumar yadav  (8 years ago)

Given that program size=n
Memory Size= square root(10n)
because program size is increased by 1%
so now size will be = n+n/100;
=101n/100
now the memory size wil be= square root of 101n/100;
more memory required in %= (10.05-10)*100/10=0.5%
so 0.5 will be the right ans

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Mohit Dhiman  (11 years ago)

Initially size=N, memory=100N
size increased by 1%, means new size=1.1N, new memory=100*1.1N=110N
Percentage increase in memory=10%
Ans= 10% (note-none of the options is correct.)

Is this solution Helpfull? Yes | No (5)  

jitendra yadav  (11 years ago)

Initial size= N , memory= 100N
size increased = 1% ,so total size= N+(N/100)=101N/100,
so memory increased m= square root of (100*(101N/100)=1%
so answere = 1%

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