Latest general Aptitude Question SOLUTION: Two water taps together can fill a tank in 9(3/8) hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately, then how much time is requ

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(#M40010623) GENERAL question Keep an EYE

Two water taps together can fill a tank in 9(3/8) hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately, then how much time is required to fill the tank separately by each tap?

Asked In general Devendra Marghade (12 years ago)

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PARAG KAMRA  (12 years ago)

Let time taken by tap with smaller diameter to fill tank = x hours
Work done in 1 hour = 1/x
time taken by tap with bigger diameter to fill tank = (x - 10) hours
Work done in 1 hour = 1/(x - 10)
1/x + 1/(x - 10) = 8/75

8x^2 - 230x + 750 = 0
4x^2 - 115x + 375 = 0
4x^2 - 100x - 15x + 375 = 0

x = 25 or x = 3.75
x = 3.75 rejected because then x - 10 < 0
So x = 25
Time taken by pipes are 25 hours and 15 hours(ans)

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jomon v j  (12 years ago)

let the small pipe take x hours then larger pipe take x-10 hours to fill seperately

then 1/x+/x-10 = 8/75

2x-10/x²-10x= 8/75

150x-750 =8x²80x

8x²-230x+750=0

4x²-1150X+375 =0

SOLVING X=25,15/4

BUT 15/4 IS NOT POSSIBLE (15/4-10 < 0)

X= 25 ,X-10 =15

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