Latest TCS Aptitude Question SOLUTION: if m is an odd integer and n an even integer, which of the following is definitely odd? a)(2m+n)(m-n) b)(m+n^2)(m-n^2) c)m2+mn+n2 d)m+n

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(#M40010708) TCS Numerical Ability question Keep an EYE

if m is an odd integer and n an even integer, which of the following is definitely odd?
a)(2m+n)(m-n)
b)(m+n^2)(m-n^2)
c)m2+mn+n2
d)m+n

Asked In TCS krishnaprasad TATA (11 years ago)

Unsolved Read Solution (23)

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Read Solution (23) :

PARAG KAMRA  (11 years ago)

m+n will be always odd,if one number is odd,and other is even ,then it always odd,
so d)m+n is right answer(ans)

Is this solution Helpfull? Yes (60) | No (7)  

Rajashree Hazra  (10 years ago)

You just remember the following odd ± odd = even; even ± even = even; even ± odd = odd
Also odd x odd = odd; even x even = even; even x odd = even.

Is this solution Helpfull? Yes (7) | No (4)  

Hemkant dewangan  (10 years ago)

D is the right answer
odd+ even= odd

Is this solution Helpfull? Yes (3) | No (3)  

saravanan  (9 years ago)

D) m+n will be the definite answer

Is this solution Helpfull? Yes (3) | No (2)  

Sumit paul  (8 years ago)

both c and d will be correct for this question

Is this solution Helpfull? Yes (3) | No (2)  

Chandrajit Nandy  (8 years ago)

Both C and D are correct....but since its a dummy question...thus selecting a particular answer may cause u negative marking..thus advised not to attend this type of questions with multiple answers....

Is this solution Helpfull? Yes (3) | No (2)  

Nemai Layek  (8 years ago)

This is a very tricky question. If we put any value at option (c) and (d) both will give us odd result.
But option C is not a correct one. Because the actual expression is m^2+m*n+n^2. Now this can be written as (m^2+m)*(n+n^2) which gives us even result.... u can check this out.... So option (d) is "definitely odd".

Is this solution Helpfull? Yes (3) | No   

ankit  (9 years ago)

m+n suppose m=1 & n=0

Is this solution Helpfull? Yes (2) | No   

PANKAJ  (8 years ago)

m+n is definitely odd

Is this solution Helpfull? Yes (2) | No (1)  

Rajat Agarwal  (9 years ago)

m+n is definitely odd.
sum of even and odd is always odd.

Is this solution Helpfull? Yes (1) | No   

debanjan ghosh  (8 years ago)

The odd number is (m+n ) because sum of an even number and an odd number is always an odd number.

Is this solution Helpfull? Yes (1) | No   

s sri sarvani  (8 years ago)

y not option b is correct can some oone explain?

Is this solution Helpfull? Yes | No   

PANKAJ  (8 years ago)

Ans is option d (m+n) always odd

Is this solution Helpfull? Yes | No (1)  

PRITHWISH CHAKRABORTY  (8 years ago)

the_answer_is_(d).

Is this solution Helpfull? Yes | No   

Ramjivan bishnoi  (8 years ago)

very easy questiion

Is this solution Helpfull? Yes | No   

sneha gogikar  (8 years ago)

sum of even and odd no is always odd
so, m+n is definitely odd

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dibyendu mukherjee  (8 years ago)

both c & d

Is this solution Helpfull? Yes | No (4)  

swastika  (8 years ago)

C is incorrect.... you can try it with any odd and even number pair. For example (i) (7,4) 7x2+7x4+4x2 => 14+28+8 = 50. (ii) (1,2) 1x2+1x2+2x2 = 2+2+4 = 8.
D is the correct ans only.

Is this solution Helpfull? Yes | No (2)  

swastika  (8 years ago)

How C & D both are correct? Can anyone please quote some example in favor of option C !!!!

Is this solution Helpfull? Yes | No   

Keerthy.S.G  (8 years ago)

is it a dummy ques or the ans is d...but it seems both c and d satisfies the condition..

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sivaram  (7 years ago)

give any value for option c the sum number is ending with odd.so ans is c

Is this solution Helpfull? Yes | No   

Abhishek kumar  (5 years ago)

C and D (Original Answer given as D)
You just remember the following odd ± odd = even; even ± even = even; even ± odd = odd
Also odd × odd = odd; even × even = even; even × odd = even.

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JOYRAJ PAUL  (2 years ago)

b) is the right answer (m+n^2) (m-n^2)

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