Latest TCS Aptitude Question SOLUTION: The base address of a 2-D integer array NUMS of dimension 5*7 is 3000. What will be the address of element NUMS[3][6], if array indices start from 0 and each integer takes two byt

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The base address of a 2-D integer array NUMS of dimension 5*7 is 3000.
What will be the address of element NUMS[3][6], if array indices start from 0 and each integer takes two bytes.


a) 3056 b) 3038 c) 3054 d) 3036

Asked In TCS shyamjee kumar (12 years ago)

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Shashank Mishra  (12 years ago)

you can follow formula's directly but for ease i write it here manual working

as indices starts from 0 so nums[3][6] means you have to access 7th element of 4th row (as i mentioned index starts from 0 ). so before access this element we have to compute 3 rows and 6 elements of 4th row hence
(3 rows * elements in row * size)+( 6 elements * size) so that
(3*7*2)+(6*2)=54 so
address of NUMS[3][6]=base+54 = 3054
answer is c)3054

Is this solution Helpfull? Yes (19) | No   

lala  (12 years ago)

sorry for the previous solution
formula is --------base address+word*(n*(i-1)+(j-1) if starting address is (1,1)but if starting address is (0,0)no need to subtract 1 from i and j
if starting address is (0,0) then formula is base address+word*(n*i+j)
here m=5,n=7,i=3,j=6,word of 2 bytes
so answer is 3000+2*(7*(3)+(6))
3000+2*27
3054
am i right...........?........:)

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Nithin  (12 years ago)

ans:3054
array starts from Nums[0][0]=3000;
given arrar address is Nums[3][6]=Nums[3+1][4+1]=Address =28-1=27
so ans is 3000+27*2=3054

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lala  (12 years ago)

base address+word*(n*(i-1)+(j-1)
here m=5,n=7,i=3,j=6,word of 2 bytes
so answer is 3000+2*(7*(3-1)+(6-1))
3000+2*19
3038
am i right...........?........:)

Is this solution Helpfull? Yes (1) | No (9)  

harmohit  (12 years ago)

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