Latest TCS Aptitude Question SOLUTION: An athlete decides to run the same distance in 1/4th less time that she usually took. by how much percent will she have to increase her average speed?

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(#M40001086) TCS Logical Reasoning question Keep an EYE

An athlete decides to run the same distance in 1/4th less time that she usually took. by how much percent will she have to increase her average speed?

Solution

let initial velocity = u and time taken = t
since athlete decides to run the same distance in 1/4th less time,
then new time taken will be t-(t/4) = 3t/4
let the new volocity = v
then for the same distance u*t = v*(3t/4) on solving we get v = 4u/3
so increment = 4u/3 - u = u/3
so % increment in speed = 33.33%


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Asked In TCS Ragini (13 years ago)

Solved Read Solution (3)

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Read Solution (3) :

Amrit  (13 years ago)

33.33 %

Is this solution Helpfull? Yes (13) | No (8)  

Tausif Hassan  (13 years ago)

33.3%

Is this solution Helpfull? Yes (6) | No (5)  

kathiresan  (6 years ago)

(100-75)/75*100=33.33

Is this solution Helpfull? Yes | No (1)  

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