Latest exam Aptitude Question SOLUTION: If a couple plans to have ten children, how many gender sequences are possible?

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Previous Question: 8/5y-2/3=23-1/15y Next Question: find the coefficients a,b,c. log(7,(8x^6/y^4)) = a log(7,2) + b log(7,x) + c log(7,y). I do not understand the form they are seeking. I have come up with 6log(7,8)+log(7,

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If a couple plans to have ten children, how many gender sequences are possible?: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: 8/5y-2/3=23-1/15y Next Question: find the coefficients a,b,c. log(7,(8x^6/y^4)) = a log(7,2) + b log(7,x) + c log(7,y). I do not understand the form they are seeking. I have come up with 6log(7,8)+log(7,

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