Latest TCS Aptitude Question SOLUTION: What is the largest number that will divide 90207, 232585 and 127986 without leaving a remainder? a) 257 b) 905 c) 351 d) 498

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(#M40110250) TCS Numerical Ability question Keep an EYE

What is the largest number that will divide 90207, 232585 and 127986 without leaving a
remainder?
a) 257 b) 905 c) 351 d) 498

Asked In TCS Goutam singha (9 years ago)

Solved Shankha Subhra Ghosh Read Solution (23)

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Read Solution (23) :

Shankha Subhra Ghosh  (9 years ago) Best Solution

HCF is the best solution. bit its time taking.
see the numbers 90207 , 232585 , 127986.
choose 905. but its not possible because last digit must be 0 or 5.
choose 498. it is also not possible because last dight must be an even number.
only 2 left now.
its easy now to get the answer by division method :)
ans is 257.

Is this solution Helpfull? Yes (78) | No   

Vinoth  (8 years ago)

232585 - 127986 =104599
127986 - 90207 = 37779

since 37779 < 104599

v use 37779
1st 37779/257=147
37779/905=41.74....
37779/351=107.6....
37779/498=75.8....

so ans is 257

Is this solution Helpfull? Yes (13) | No   

Abhishek nkumar  (9 years ago)

ans. A .take the HCF of 90207,232585 & 127986

Is this solution Helpfull? Yes (11) | No (3)  

abhinav shrivastava  (8 years ago)

we understand that answer is the HCF of all the numbers, but we need not to actually calculate the HCF, just a little observation will help you to get through in seconds by reducing the options.. first check the numbers, and the options, as 498 is one of the options, that means, all the numbers should be even number as 498 is also an even number, but only 127986 is even so 498 is not the option, then we check the divisibility by 3, so 232585 is not divisible by 3, that means amongst the options, one which is divisible by is not the correct one, 351 is not the answer, then for being divisible by 905, numbers should be divisible by 5 as well, but only 232585 is divisible...so 905 is also not the correct answer, so we are left with 257 as correct answer... :) :)

Is this solution Helpfull? Yes (10) | No   

vainkat raman   (9 years ago)

subtract 2 to 1,2 to 3 then u can tak a hcf of two numbers

Is this solution Helpfull? Yes (9) | No (4)  

RAHUL RANJAN KASHYAP  (9 years ago)

A) 257
easily u can chk by division

Is this solution Helpfull? Yes (3) | No (5)  

Surit Datta  (9 years ago)

as division by 905 and 498 is not possible
so either 257 or 351
now HCF them
we get 257 as the answer.

Is this solution Helpfull? Yes (3) | No   

indrani banerjee  (9 years ago)

first we can find out H.C.F of the three number given,, and will check with the given calculator which option adjust correctly. therefore
option A-257 fitts correctly,..

shortest way to solve during tcs written exam. :)

Is this solution Helpfull? Yes (3) | No (9)  

ANUJ PAL  (9 years ago)

wil u plss explain it clearly

Is this solution Helpfull? Yes (2) | No   

Amoolya  (8 years ago)

eliminate 905 and 498.check either by divisibility rule or gcd.for e.g. 351 is divisible by 3 but 232585 is not divisible by 3....

Is this solution Helpfull? Yes (1) | No (1)  

samarth jain  (7 years ago)

351
by process of elimination

Is this solution Helpfull? Yes (1) | No   

rinku gajbhiye  (9 years ago)

A is a correct answer

Is this solution Helpfull? Yes | No (2)  

RAVI RANJAN DUBEY  (9 years ago)

257 is the correct answer

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nilesh uttam gunjal  (9 years ago)

257 divisible to all nunber

Is this solution Helpfull? Yes | No (1)  

shashank  (9 years ago)

ANS IS ; A

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harika  (9 years ago)

pls explain clearly..

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dee hack kr  (9 years ago)

hcf of no
use elimination method and reject 905 and 498

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Akanksha Tripathi  (9 years ago)

257 is the answer

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chandrakala  (9 years ago)

x/6+x/4+x/6+32=x

24x-14x=768

768/10=76.7(app.77)

77+13=90
ans=90

Is this solution Helpfull? Yes | No (2)  

Soumen Dofadar  (8 years ago)

just find the gcd......its 257

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Dipanjan Roy Nandi  (8 years ago)

by doing HCF
ans will be a) 257

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swati yadav  (8 years ago)

257)90207(351
771
-----------------
1310
1285
-------------------
257
257
--------------------
000
so ans is 257

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RM ARUNACHALAM  (4 years ago)

Given numbers are 90207,127986 and 232585.

To Get the greatest number which divides given numbers without leaving a remainder.

i.e find the HCF of given numbers.
90207=3*3*3*13*257
127986=2*3*83*257
232585=5*181*257
=> 257 is the largest number.

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