Latest TCS Aptitude Question SOLUTION: . In a rectanglular coordinate system, what is the area of a triangle whose vertices whose vertices have the coordinates (4,0), (6, 3) adn (6 , -3)

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. In a rectanglular coordinate system, what is the area of a triangle whose vertices whose vertices have the coordinates (4,0), (6, 3) adn (6 , -3)

Asked In TCS krati (11 years ago)

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arumoy  (11 years ago)

Given coordinates are(4,0),(6,3)and (6,-3).
here base=3-(-3)=6
height=6-4=2
hence area=1/2*6*2=6(ans).

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Nikhil Mahapatra  (11 years ago)

After Drawing these point in graph, we will get two triangles:
base is 2 & height is 3 for both the triangles .

Triangle 1 Area => 1/2 * b * h => 1/2 * 2 * 3 => 3
Triangle 2 Area => 1/2 * b * h => 1/2 * 2 * 3 => 3

Area of Triangle 1 + Area of Triangle 2 => 3 + 3 => 6

Answer is 6.

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DIBYENDU PRAMANIK  (11 years ago)

let
(4,0)=(x1,y1)
(6,3)=(x2,y2)
(6,-3)=(x3,y3)
area=|[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]/2|=6 ans

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Sanoj  (11 years ago)

Ans will be 6 units...Because if you draw the figurse it will make base as 6 unit and height as 2 unit..now using the formula(1/2)*base*height ......it will be 6

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debopama sarkar  (11 years ago)

from the question the altitude of triangle is 2 units(6-4) and base is 6 units(3+3). so, area is 0.5*6*2=6 units

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rohit  (11 years ago)

the graph drawn by the given coordintes gives the value of altitude of triangle as 6-4=2 and base i given as 3 towards +ve y axix and 3 towards -ve y axis i.e3+3=6 so by formula : 1/2*2*6=6 ans.6

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