Latest TCS Aptitude Question SOLUTION: three farmer paid rs 1000 for small pastur. one farmer gazed his 9 mules, another his 12 cows for twice and last man put in sowe goats for 2.5 times as the second man's cow and pai

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three farmer paid rs 1000 for small pastur. one farmer gazed his 9 mules, another his 12 cows for twice and last man put in sowe goats for 2.5 times as the second man's cow and paid half the cost of the pasture.
can u find out how many goat did the last man have,if 6 cows eat as much as 4 mules,and 10 goat as muchas 3 cows?

Asked In TCS subha das (11 years ago)

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RAVI KIRAN  (11 years ago)

Please any one solve this question

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PARTHIBAN SMVEC  (11 years ago)

30 only
goat=2.5 times of cow
=2.5*12=30

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atchutha reddy ambala  (9 years ago)

third farmer paid rs500
first and second farmers paid rs500 for 9 mules and 24 cows(as 12 cows eat twice 9 mules)
given 6cows=4mules and 6 cows = 20 goats
now 9mules =45 goats and 24 cows = 80 goats total 125 goats for 500rs
divide 125 goats or 500rs in 2 and half parts ie 50,50,25 or 200,200,100
now goats of third farmer = 50 goats as eaten two and half time and per goat rs4
first farmer = 9 mules = 45 * 4=180
second farmer = 24 cows= 80*4=320

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Aritra Ray  (8 years ago)

10 goats = 3 cows-1 time
>> 40 goats = 12 cows-1 time
>>80 goats = 12 cows - 2 times....(i)
Similarly, 6 cows = 20 goats = 4 mules-1 time
>> 45 goats = 9 mules-1 time.........(ii)
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Adding (i)+(ii), we get 9 mules-1 time + 12 cows-2 times = 125 goats-1 time
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By the problem, 125 goats-1 time = Rs 500
1 goat-1 time = 500/125 = Rs 4.......(iii)
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Now, according to 2nd condition, x goats - 2.5times = Rs. 500
x goats - 1 time = 500/2.5 = Rs 200
1 goat - 1 time = Rs 200/x...........(iv)
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Equating (iii) & (iv), we get 200/x = 4 or, x = 50
Thus the man had 50 goats.
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