Latest TCS Aptitude Question SOLUTION: 19 Two c ars A and B start simultaneously fro m two points P and Q with c ertain speeds towar ds eac h other. After reaching a point R, speed of A dec reases by 1/3. It then meet

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19 Two c ars A and B start simultaneously fro m two points P and Q with c ertain speeds
towar ds eac h other. After reaching a point R, speed of A dec reases by 1/3. It then
meets B at a po int S where SQ = 2PR. If he speed of A had beco me 1/3 less at the mid
point of RS the c ars would hav e met at T w here ST = PR/4. Find RS: PR.
(a) 5: 1 (b) 6: 1 (c) 8:1 (d) 10:1

Asked In TCS vishnupriya.O (11 years ago)

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Jagruti Mandir  (11 years ago)

condition (1)

(PR/Sa)+(3SR/2Sa)=2PR/Sb-------(1)

condition (2)

(PR+RS/2)/Sa+3/2Sa=QT/Sb

(8PR+4RS+6RS+3PR)/8Sa=QT/Sb=2PR/Sb-----(2)

dividing (1) by (2)

(11PR+10RS)/(4PR+6RS)=QT/PR

ON SIMPLIFICATION,(put,PQ=PR+RS+ST+TQ)

(11PR+10RS)/(4PR+6RS)=7/4

SOLVING FURTHER,

RS/PR=8:1

so,option (C)

Is this solution Helpfull? Yes (3) | No (2)  

SOUGATA PAUL  (11 years ago)

can u pls explain how do u form the equations ?

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