Latest Syntel Aptitude Question SOLUTION: When numbers are written in base b, we have 12 x 25 = 333, the value of b is? a) 8 b) 6 c) None d) 7

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(#M40112594) SYNTEL Numerical Ability question Keep an EYE

When numbers are written in base b, we have 12 x 25 = 333, the value of b is?
a) 8
b) 6
c) None
d) 7

Asked In Syntel MATHU (9 years ago)

Unsolved Read Solution (7)

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Satya B  (9 years ago)

ans d) 7
12 ,25 and 333 in decimal form can be written as (1*b^1 + 2*b^0) , (2*b^1 + 5*b^0), (3*b^2+3*b^1 + 3*b^0)

12 *25 = 333
(1*b^1 + 2) * (2*b^1 + 5*) = (3*b^2+3*b^1 + 3)
b^2+ 9b + 10 = 3b^2 + 3b + 3
b^2 -6b -7 = 0
b^2 - 7b + b - 7 =0
(b-7)(b+1)=0
b=7 or b=-1
base cannot be a negative value so b=7

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syed kashif ullah  (9 years ago)

option d 7.

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R K NADHIYA  (9 years ago)

(1*b^1+2)*(2*b^1+5)=(3*b^2+3*b+3)

(b+2)(2b+5)=3b^2+3b+3

b^2 -6b -7=0
b=7 or b=-1

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Ayushi Agarwal  (8 years ago)

ans d) 7
12 ,25 and 333 in decimal form can be written as (1*b^1 + 2*b^0) , (2*b^1 + 5*b^0), (3*b^2+3*b^1 + 3*b^0)

12 *25 = 333
(1*b^1 + 2) * (2*b^1 + 5*) = (3*b^2+3*b^1 + 3)
b^2+ 9b + 10 = 3b^2 + 3b + 3
b^2 -6b -7 = 0
b^2 - 7b + b - 7 =0
(b-7)(b+1)=0
b=7&-1

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sai prasanna  (8 years ago)

answer is 7

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Tushar Bedekar  (8 years ago)

Ans is 7 [(1*b^1+2)(2*b^1+5)=(3*b^2+3b^1+3)]

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bhupendra  (8 years ago)

7


(b+2)(2b+5)=3b^2+3b+3

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