Latest TCS Aptitude Question SOLUTION: a cow is sold at a profit of 20% and hourse at loss of 10%. The overall gain is 4000. the cost price of cow and hourse is 200000. find cost price of cow

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Profit and Loss

TCS Question Papers: TCS Interview Experience(91) TCS Company Profile

(#M40113016) TCS Numerical Ability question profit loss Keep an EYE

a cow is sold at a profit of 20% and hourse at loss of 10%. The overall gain is 4000. the cost price of cow and hourse is 200000. find cost price of cow

Asked In TCS vinit (10 years ago)

Unsolved Read Solution (14)

Is this Puzzle helpful?   (15)   (2) Submit Your Solution Profit and Loss

Read Solution (14) :

Surit Datta  (10 years ago)

let cost price of cow is x
then cost price of horse is (200000 - x)
according to the question,
1.2*x + (200000 - x)*0.9 = 204000
solving this we get
x = 80000
so cost price of cow is 80000

Is this solution Helpfull? Yes (17) | No   

balu  (10 years ago)

c+h=200000,
(120/100)c+(90/100)(200000-c)=204000,
c=240000/3=80,000

Is this solution Helpfull? Yes (2) | No   

abhik k. dey  (10 years ago)

let price of cow is x
then price of horse is (2,00,000-x)

so as per the question (1.2x+.9(2,00,000-x))=2,04,000
or, x=80,000

so the price of cow is 80,000

Is this solution Helpfull? Yes (1) | No (1)  

tamil selvi  (10 years ago)

given: x+y=200000. let the c.p of cow be x and the horse be (x-2,00,000)
20% of x + 10% of (x - 200000) = 4000( gain)
x/5 + (x - 200000)/10 = 4000
3x/10 = 4000 + 200000 = 2,40,000
x= 80,000

Is this solution Helpfull? Yes (1) | No (1)  

SREEKANTH THUPILI  (10 years ago)

80000--->2/5*200000

Is this solution Helpfull? Yes (1) | No   

amanpreet singh  (10 years ago)

let cost price of cow is X
let cost price of HORSE is Y
OVERALL GAIN IS (1.2X+0.9Y)-(X+Y)=4000
AND X+Y=200000
AFTER SOLVING
X=80000

Is this solution Helpfull? Yes (1) | No   

Ankita Sharma  (10 years ago)

let the c.p. of cow be Rs.x, then the c.p. of horse is Rs.(200000-x)
20% of x-10% of (200000-x) = overall gain
20*x/100-x/100*(200000-x)=4000
30x-2000000=400000
30x=2400000
x=2400000/30
x=80000
Thus, c.p. of cow = Rs. 80000

Is this solution Helpfull? Yes | No   

shivangi  (10 years ago)

c.p=200000
profit=4000
let c.p of cow =x
c.p of horse=200000-x
profit=s.p-c.p
s.p of cow=0.2x+0.9(200000-x)
4000=.2x+.9(200000-x)-200000
solving above equation,we get
x=80000

Is this solution Helpfull? Yes | No (1)  

priyanka jadhavar  (10 years ago)

Let c.p. of cow is x
then c.p. of horse is (200000-x),
profit %=100+20/100=1.2,loss%=100-10/100=0.9,
overall gain=4000,
solving this we get the answer is
(1.2*x)+(200000-x)*0.9=204000,
x=80000.cp of cow is 80000

Is this solution Helpfull? Yes | No   

Anwar Basha  (10 years ago)

Let Cow cost price is X.COst price of Horse is Y.
He mentioned that X+Y=200000
Y=200000-x
Cow is sold at a profit of a 20% So 20% of x becomes 0.2x
Horse is sold at a loss of 10% so 10% of Y becomes 0.1y.
0.2X-0.1Y=4000
0.2X-0.1(200000-x)=4000
0.2X-20000+0.1X=4000
0.3X=4000+20000
X=8000/-

Is this solution Helpfull? Yes | No (2)  

PRIYADHARSHINI S  (10 years ago)

ans: 80,000

Is this solution Helpfull? Yes | No   

Aamir Sohail  (10 years ago)

overall gain=s.p -c.p
4000=(90(200000-x)/100)+(120x/100)-(200000)
30x/100=204000
x=80,000

Is this solution Helpfull? Yes | No   

naveen  (9 years ago)

1.2(cow)+0.9(horse)=200000-4000=196000.
then
price of cow is [(196000)/(2.1)]*(1.2)=rs1,12,000 /-
price of horse is [(196000)/(2.1)]*(0.9)=rs 84000/-

Is this solution Helpfull? Yes | No   

vinisha  (9 years ago)

vinisha.vinz@gmail.com

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.