Latest TCS Aptitude Question SOLUTION: a cow is sold at a profit of 20% and hourse at loss of 10%. The overall gain is 4000. the cost price of cow and hourse is 200000. find cost price of cow

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a cow is sold at a profit of 20% and hourse at loss of 10%. The overall gain is 4000. the cost price of cow and hourse is 200000. find cost price of cow

Asked In TCS vinit (9 years ago)

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Surit Datta  (9 years ago)

let cost price of cow is x
then cost price of horse is (200000 - x)
according to the question,
1.2*x + (200000 - x)*0.9 = 204000
solving this we get
x = 80000
so cost price of cow is 80000

Is this solution Helpfull? Yes (17) | No   

balu  (9 years ago)

c+h=200000,
(120/100)c+(90/100)(200000-c)=204000,
c=240000/3=80,000

Is this solution Helpfull? Yes (2) | No   

abhik k. dey  (9 years ago)

let price of cow is x
then price of horse is (2,00,000-x)

so as per the question (1.2x+.9(2,00,000-x))=2,04,000
or, x=80,000

so the price of cow is 80,000

Is this solution Helpfull? Yes (1) | No (1)  

tamil selvi  (9 years ago)

given: x+y=200000. let the c.p of cow be x and the horse be (x-2,00,000)
20% of x + 10% of (x - 200000) = 4000( gain)
x/5 + (x - 200000)/10 = 4000
3x/10 = 4000 + 200000 = 2,40,000
x= 80,000

Is this solution Helpfull? Yes (1) | No (1)  

SREEKANTH THUPILI  (9 years ago)

80000--->2/5*200000

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amanpreet singh  (9 years ago)

let cost price of cow is X
let cost price of HORSE is Y
OVERALL GAIN IS (1.2X+0.9Y)-(X+Y)=4000
AND X+Y=200000
AFTER SOLVING
X=80000

Is this solution Helpfull? Yes (1) | No   

Ankita Sharma  (9 years ago)

let the c.p. of cow be Rs.x, then the c.p. of horse is Rs.(200000-x)
20% of x-10% of (200000-x) = overall gain
20*x/100-x/100*(200000-x)=4000
30x-2000000=400000
30x=2400000
x=2400000/30
x=80000
Thus, c.p. of cow = Rs. 80000

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shivangi  (9 years ago)

c.p=200000
profit=4000
let c.p of cow =x
c.p of horse=200000-x
profit=s.p-c.p
s.p of cow=0.2x+0.9(200000-x)
4000=.2x+.9(200000-x)-200000
solving above equation,we get
x=80000

Is this solution Helpfull? Yes | No (1)  

priyanka jadhavar  (9 years ago)

Let c.p. of cow is x
then c.p. of horse is (200000-x),
profit %=100+20/100=1.2,loss%=100-10/100=0.9,
overall gain=4000,
solving this we get the answer is
(1.2*x)+(200000-x)*0.9=204000,
x=80000.cp of cow is 80000

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Anwar Basha  (9 years ago)

Let Cow cost price is X.COst price of Horse is Y.
He mentioned that X+Y=200000
Y=200000-x
Cow is sold at a profit of a 20% So 20% of x becomes 0.2x
Horse is sold at a loss of 10% so 10% of Y becomes 0.1y.
0.2X-0.1Y=4000
0.2X-0.1(200000-x)=4000
0.2X-20000+0.1X=4000
0.3X=4000+20000
X=8000/-

Is this solution Helpfull? Yes | No (2)  

PRIYADHARSHINI S  (9 years ago)

ans: 80,000

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Aamir Sohail  (9 years ago)

overall gain=s.p -c.p
4000=(90(200000-x)/100)+(120x/100)-(200000)
30x/100=204000
x=80,000

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naveen  (9 years ago)

1.2(cow)+0.9(horse)=200000-4000=196000.
then
price of cow is [(196000)/(2.1)]*(1.2)=rs1,12,000 /-
price of horse is [(196000)/(2.1)]*(0.9)=rs 84000/-

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vinisha  (9 years ago)

vinisha.vinz@gmail.com

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