Latest TCS Aptitude Question SOLUTION: If 30 men working 7 hours per day can do a work in 18 days in how many days will 21 men working 8 hours a day do the same work?

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If 30 men working 7 hours per day can do a work in 18 days in how many days will 21 men working 8 hours a day do the same work?

Asked In TCS (11 years ago)

Unsolved Read Solution (8)

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Read Solution (8) :

Vivek.K  (11 years ago)

for these problems follow the formulae ((M1)*(D1)*(H1))/(W1)= ((M2)*(D2)*(H2))/(W2)

WHERE M- men or women
H- hours
D-days
W- work
here work is same .therefore W1=W2
M1*D1*H1=M2*D2*H2

30*7*18=21*8*x

implies X=22.5 days

Is this solution Helpfull? Yes (29) | No   

K@t$  (11 years ago)

time taken=22.5 days

Is this solution Helpfull? Yes (12) | No (1)  

Binayprabhu  (11 years ago)

m1t1d1/w1=m2t2d2/w2 ...w1=w2{same work}then d2=m1t1d1/m2t2
30*7*18/21*8=d2...ans=45/2=22.5

Is this solution Helpfull? Yes (4) | No   

manikumar  (11 years ago)

m1*d1*h1=m2*d2*h2
30*7*18=21*d2*8
by solving we get 22.5 days

Is this solution Helpfull? Yes (4) | No   

supriya guin  (11 years ago)

30men 7hrs 18 days
1men 7hrs 18/30days
1men 1hrs 18/(30*7)days
21men 8hrs 18*21*8/(30*7)=14.4days

Is this solution Helpfull? Yes (1) | No (22)  

sarumathipriya  (5 years ago)

Formula
P1*H1*D1=P2*H2*D2
here
P=person
H=hours
D=number of days
30*7*18=21*8*x
x=(30*7*18)/(21*8)
x=22.5 days

Is this solution Helpfull? Yes (1) | No   

Archana  (8 years ago)

280 seconds

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Kumari Aparajita  (4 years ago)

M1*d1*h1=m2*d2*h2
So, 30*7*18=21*d2*8
d2=45/2=22.5

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