Latest exam Aptitude Question SOLUTION: Find the root(s) of : 8/x-3 -3= 2-3x/x=3 (Note: the subtract 3 is not part of the denominator) Can someone PLEASE help me with this???

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Previous Question: 3. How do I solve this equation using factoring? Thank you. x^2 + 6 = -5x Next Question: Given: (segment)AB is parallel to (segment)CD; (segments)AD and CB are congruent; (segments)AD and CB bisect each other at X. Prove: triangle ABC is congruent to triangle CDA

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Find the root(s) of : 8/x-3 -3= 2-3x/x=3 (Note: the subtract 3 is not part of the denominator) Can someone PLEASE help me with this???: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: 3. How do I solve this equation using factoring? Thank you. x^2 + 6 = -5x Next Question: Given: (segment)AB is parallel to (segment)CD; (segments)AD and CB are congruent; (segments)AD and CB bisect each other at X. Prove: triangle ABC is congruent to triangle CDA

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