Latest IBM Aptitude Question SOLUTION: 1) 1/3,1/2,1/4,7/3,7/2,17/4,13/3,13/2,_? 2) 18,6,24,4,30,10,12,2,6,_? 3) 9,15,26/3,29/2,25/3,14,8,27/2,_? 4) 5,50,10,40,15,30,20,20,_? 5) 1.25,3,7.1,1.50,1.81,_? 6) 7/6,2/3,11/6,13

1) denominator is 3,2,4,3,2,4,............
at numerator 6 is added after 3 terms
so next terms are: 13/4, 19/3, 19/2, 19/4, ..............

3)5,50,10,40,15,30,20,20,_?
Ans: Take the series as Even and Odd
For every even number 10 will be reduced 50,,40,30,20
for every odd number 5 willl be increased 5,10,15,20
so the answer is 25

1)33/4,19/2,19/3

3) We an write the series in this way
9,15,26/3,29/2,25/3,14,8,27/2,_?

27/3, 30/2,26/3,29/2,25/3,28/2,24/3,27/2,23/3
the difference is 3.

7)i think ans is 131
5*2=10+7=17
17*2=34+3=37
37*2=74-7=67
67*2=174-3=131
multiply with 2 then alternatively add n sub +7,+3,-7,-3

6) add the first two terms to get the third term- 7/6+2/3=11/6... 13/6+5/2=28/6..ans=28/6

4) It is a combo of two series
1-> 5,10,15,20 next 25
2-> 50,40,30,20 next 10

so next two terms are 25,10

183=6
24/6=4
30/3=10
12/6=2
6/3=2
next term is 2

9)ans:17
by seeing alternative numbers we have first difference is 1 and after that for the next series add 5 and after that also add 5.

sneha deepthi small correction
8)251.5
251.5-89.5=162(54*3)

2) ans 2
18/6=3
24/4=6
30/10=3
12/2=6
6/2=3

1.
addeded by 2,3,4
1/3 +2=7/3
1/2 +3=7/2
1/4 +4=17/4

7/3 +2=13/3
7/2 +3=13/2
17/4 +4=33/4

2.{18,6},[24,4],{30,10},[12,2],{6,_}

every pair in {} is divided by 3
and every pair in [] is divided by 4
and this continues alternatively

18/3 = 6 ... 24/6 = 4
30/3 = 10 .. 12/6 = 2
6/3 = 2
Ans : 2

3.
2 Series:
1st Series: 9, 26/3, 25/3, 8, ? 2nd Series: 15, 29/2, 14, 27/2

1st Series can be rewritten as -> 27/3, 26/3, 25/3, 24/3, ? => here it decreases by 1/3
and 2nd series can be written as -> 30/2 , 29/2 , 28/2 , 27/2 ..... => here it decreases by 1/2

So Next number will be: 24-1/3 - 1/3 = 23/3 Ans

4.Ans: 25
5,10,15,20; (+5)Series. Next one will be 25
50,40,30,20; (-10)Series. Next on will be 10

5.this question is wrong, the correct series will be
1.25,3,7.1,1.50,1,8.1,1.75,-1,?

ans=9.1
in that series +.5,-2,+1 added as so that no. would be 3rd no.right to that no.
1.25+.5=1.50
3-2=1
7.1+1=8.1
1.50+.25=1.75
1-2=-1
8.1+1=9.1

6.NA

7.7) 5,17,37,67,_?

5 , 17 , 37 , 67 , _?
12 20 30 42
8 10 12

so ans is :: 67 + 42 = 109

8.Next number is 251.5

11.5 =11.5
11.5 +(6) = 17.5
17.5 +(6*3) = 17.5 + 18 = 35.5
35.5 +(18*3) = 35.5 + 54 = 89.5
89.5 +(54*3) = 89.5 + 162 = 251.5

9.
3-8=-5
2-7=-5
7-12=-5
12-17=-5
ans is 17

1)33/4
2)2
3)23/3,13,22/3,25/2
4)25
5)
6)
7)101
8)251.5
9)
10)

8) 272.5
Explanation: 17.5 -11.5 = 6
35.5-17.5=18 (6*3)
89.5-35.5=54(18*3)
272.5-89.5=162(54*3)

Pls post sol for 3rd one

6) 7/6,2/3,11/6,13/6,5/2,_?
7/6+2/3=11/6
13/6+5/2=28/6

So ans is :14/3

3)23/3 since diff.b/w alternate nos. is 1/3

ANS for 1)33/4
2) 12

we have to take alternative numbers those are 5,10,15,20
after that 50,40,30,20.
for the first sequence difference is 5&for the second sequence difference is 10
ans is 25.

9) ans is 17
1st two nos diff 8-3=5 then add 3rd no to it (5+2=7)
12-7=5 then(5+12=17)

5,17,37,67
2^2+1
4^2+1
6^2+1
8^2+1
9^2+1

2) 18 6 = 6*3
24 4 =4*6
30*10=10*3
12 2=2*6
6 x= 2*3

plz expain 3rd one..

5) 1.25+0.25=1.50+0.25=1.75

1> 33/4
3>23/3
4>25
6>11/3
8>272.5
9>17

9. 8-3=5
7-2=5
12-7=5

So obviously 17-12=5
ans : 17

10) 1.25,3,7.1,1.50,1.81
take 1.25+0.25=1.5
1.5+0.25=1.75
so series will be 1.25,3,7.1,1.50,1.81,x,1.75
to find x
3*2+1.1=7.1
similarly 1.81*2+1.1=4.72
ans 4.72

3) ans is 23/3 bcs do +3 &-4 and divide alternatively by 3 &2. u will gt