Latest TCS Aptitude Question SOLUTION: The Mean of three numbers is 10 more than than the least number and 15 less than the highest. Their median is 5. Find the sum of the three numbers.

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(#M40011593) TCS Numerical Ability question The Mean of three numbers is 10 more than than the least number and 15 less than the highest. Their Keep an EYE

The Mean of three numbers is 10 more than than the least number and 15 less than the highest. Their median is 5. Find the sum of the three numbers.

Asked In TCS Priyabrat Padhy (12 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

sathyapriya  (12 years ago)

given: x+y+z/3=m
y=5;
m=x+10;x=m-10;
z=m+15
sub in above give eq u will get m= 10;
sub in x, y, z =0,5,25=total=30

Is this solution Helpfull? Yes (29) | No (3)  

Shashank Mishra  (12 years ago)

numbers are 0 5 25
so sum is =30

Is this solution Helpfull? Yes (26) | No (6)  

krishna reddy chemikela  (9 years ago)

options are: a) 30 b) 20 c) 5 d) 25
option itself shows
30 only the divisible of 3.
so ans is 30.

Is this solution Helpfull? Yes (9) | No   

naveenkumar yenda  (9 years ago)

mean of 3 no's x+y+z/3=10
then x+y+z=30
sum of 3 no's=30

Is this solution Helpfull? Yes (8) | No (4)  

manikandan m  (10 years ago)

options are: a) 30 b) 20 c) 5 d) 25
option itself shows
30 only the divisible of 3.
so ans 30.

Is this solution Helpfull? Yes (6) | No   

kajal sharma  (12 years ago)

@Abhishek jain
median is the middle term of numbers in case of odd nos
& in case of even nos median is (n/2)th term + (n/2 + 1)th term
& here 2nd term is 5(median)

Is this solution Helpfull? Yes (4) | No   

subhasis ghosh  (9 years ago)

(x-10)+5+(x+15)=3x
x=10
so total sum =30

Is this solution Helpfull? Yes (3) | No (1)  

Abhishek Jain  (12 years ago)

@shashank- how can we calculate median?

Is this solution Helpfull? Yes (2) | No (3)  

Abhishek Jain  (12 years ago)

thanx kajal

Is this solution Helpfull? Yes (2) | No   

R.S.L.manasa  (12 years ago)

answer is 30

Is this solution Helpfull? Yes (1) | No   

Susmita Das  (9 years ago)

Current trend

Is this solution Helpfull? Yes | No   

prajval  (8 years ago)

Distnace between House and T junction = 20 x 2 = 40.
ie., B reached T at 11 am.
B continued to right after 11 am and travelled upto 2. So distance covered by him = 3 x 40 = 120
A reached T at 12 noon and travelled upto 2 So distanced travelled by him = 2 x 20 = 40
So total distance between them = 120 + 40 = 160 km

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