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(#M40116073) TCS Numerical Ability question probablity Keep an EYE

Find the probability that a leap year selected at random will have 53 Sundays

Asked In TCS vishnu (10 years ago)

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Read Solution (7) :

manorama rai  (10 years ago)

A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days.

The remaining 2 days may be any of the following :

(i) Sunday and Monday

(ii) Monday and Tuesday

(iii) Tuesday and Wednesday

(iv) Wednesday and Thursday

(v) Thursday and Friday

(vi) Friday and Saturday

(vii) Saturday and Sunday

For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.

n(S) = 7

n(E) = 2

P(E) = n(E) / n(S) = 2 / 7

Is this solution Helpfull? Yes (19) | No   

sai ramya  (10 years ago)

leap year means 366 days i.e 52 weeks and 2 extra days..
extra two days may be (Mon,Tue)or(Tue,Wed)or(Wed,Thu)or(Thu,Fri)or(Fri,Sat)or(Sat,Sun)
i.e n(A)=2 and n(S)=7
P(n)=n(A)/n(S)=2/7

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Kaju Gupta  (10 years ago)

give the range of years.

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Shintala Divya  (10 years ago)

leap year=52 weeks+2 odd days
these odd days can be (sat,sun),(sun,mon),(mon,tues),(tues,wed),(wed,thr)(thr,fri)(fri,sat)
prodability=2/7..

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Himanshu Dhingra  (10 years ago)

days in leap year 366/7=52,REMAINDER=2;
so possible days on remaining two days
(i) Sunday and Monday

(ii) Monday and Tuesday

(iii) Tuesday and Wednesday

(iv) Wednesday and Thursday

(v) Thursday and Friday

(vi) Friday and Saturday

(vii) Saturday and Sunday

For having 53 Sundays in a year, one of the remaining 2 days must be a Sunday.
now total days in a week=7
probability=2/7 answer.

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kshipra sengar  (10 years ago)

ans is 2/7

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Hirak Bhattacharjee  (9 years ago)

ans is 2/7

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