Latest TCS Aptitude Question SOLUTION: Pls explain its answer with reason.. 1941^3483 + 1961^4181= find out the last 2 digits

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Pls explain its answer with reason..

1941^3483 + 1961^4181= find out the last 2 digits

Asked In TCS Nayan N (11 years ago)

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Abhishek Jain  (11 years ago)

Ans is 82...

Is this solution Helpfull? Yes (19) | No (5)  

Rakesh Kumar  (11 years ago)

I think , the two last digit should be 02.
Because the last digit is 1 in case of both numbers.
so, any power of 1 leads to 1.

for second digit :
In case of 1st number it is 4, any odd power of 4 leads to 4.
In case of 2nd number it is 6, any odd/even power of 6 leads to 6.

when last 2 digit are added ,the result will be like this 102.
so, last 2 digit is 02.

Is this solution Helpfull? Yes (19) | No (17)  

nawa  (11 years ago)

82
unit digit 1
tens digit 3*4=12
so 1st case no 121
similarly 2nd case
unit digit 1
ten digit 6*1=6
so number is 61
after adding the two no=(61+21)=82 (ans)

Is this solution Helpfull? Yes (18) | No (4)  

kajal sharma  (11 years ago)

ans is 82....

Is this solution Helpfull? Yes (10) | No (2)  

Akanksha Narula  (11 years ago)

82 is the ans.

Is this solution Helpfull? Yes (5) | No   

AS  (11 years ago)

ans is 02

Is this solution Helpfull? Yes (2) | No (6)  

satyanarayana  (11 years ago)

explain how it was solve abhishek .plz........... i can't understand.

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Nayan N  (11 years ago)

Rakesh Kumar :thanks ok...i get ur logic....u sure that is the correct answer?


n pls ,those who have posted 82 as their answers pls xplain how it comes

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sukrati pandey  (11 years ago)

answer is 02 or 82.. plz clearify !

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Priyabrat Padhy  (11 years ago)

ye qstn kaunsa clg me tcs ka hai??

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Abhishek Jain  (11 years ago)

dnt knw egertrjut

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