Factor each of the polynomials completely 14x 2 20x 6 I factored 14 to 7 2 and 6 to 2

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Latest exam Aptitude Question SOLUTION: Factor each of the polynomials completely. 14x^2 - 20x + 6. I factored 14 to 72 and 6 to 23. then the parenthesis. (7x -3)(2x -2). But what I do not understand is how this would

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(#M40116553) EXAM Numerical Ability question Keep an EYE

Factor each of the polynomials completely. 14x^2 - 20x + 6. I factored 14 to 72 and 6 to 23. then the parenthesis. (7x -3)(2x -2). But what I do not understand is how this would equal 20x. That is the part I am stuck on.

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Latest exam Aptitude Question SOLUTION: Factor each of the polynomials completely. 14x^2 - 20x + 6. I factored 14 to 7*2 and 6 to 2*3. then the parenthesis. (7x -3)(2x -2). But what I do not understand is how this would

exam Question Papers:

Maths Puzzle

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Category (66)

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Logical Reasoning (56)

Numerical Ability (85560)

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Verbal Ability (5)

(#M40116553) EXAM Numerical Ability question Keep an EYE

Factor each of the polynomials completely. 14x^2 - 20x + 6. I factored 14 to 7*2 and 6 to 2*3. then the parenthesis. (7x -3)(2x -2). But what I do not understand is how this would equal 20x. That is the part I am stuck on.

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Latest exam Aptitude Question SOLUTION: Factor each of the polynomials completely. 14x^2 - 20x + 6. I factored 14 to 72 and 6 to 23. then the parenthesis. (7x -3)(2x -2). But what I do not understand is how this would

Factor each of the polynomials completely. 14x^2 - 20x + 6. I factored 14 to 72 and 6 to 23. then the parenthesis. (7x -3)(2x -2). But what I do not understand is how this would equal 20x. That is the part I am stuck on.