Latest TCS Aptitude Question SOLUTION: In 4 years, Rajs father will be double Rajs age then. Two years ago, while his mother was twice his age that time. If Raj is going to be 32 years old 8 years from now, then what i

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In 4 years, Rajs father will be double Rajs age then. Two years ago, while his mother was twice his age that time. If Raj is going to be 32 years old 8 years from now, then what is the sum of his parents age now?

Asked In TCS Sanghmitra (9 years ago)

Solved Neeraj Maheshwari Read Solution (15)

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Read Solution (15) :

VIVEK EATHA  (9 years ago)

R.F=RAJS FATHER AGE
R=RAJS AGE
R.M=RAJS MOTHER AGE
(R.F+4)=2*(R+4)
(R.M-2)=2*(R-2)
R+8=32
therefore, R=24
therefore, R.M=46
therefore, R.F=52
R.F + R.M = 98

Is this solution Helpfull? Yes (41) | No (5)  

Neeraj Maheshwari  (9 years ago) Best Solution

98 year is ans

Is this solution Helpfull? Yes (5) | No (7)  

yamini shrivastava  (8 years ago)

if raj's present age is x
then fathers age after 4 yr=2(x+4)
mothers age 2 yrs ago =2(x-2)
and x+8=32
x=24
so fathers age=52
mothers age=46
total=98

Is this solution Helpfull? Yes (3) | No (2)  

Tanmoy Gupta  (8 years ago)

Let,
Raj's age be x
Mother and father's age be y and z respectively
2(x-2)=z
2(x+4)=y
x+8=32
x=24
solving above equations...
Y+Z=100

Is this solution Helpfull? Yes (3) | No (1)  

Soumen Dofadar  (8 years ago)

52 is the father's age and 46 is the mother's age.So 98 will be the sum

Is this solution Helpfull? Yes (2) | No   

Arunima   (8 years ago)

2(R+4)=(F+4)
2(R-2)=M-2
R+8=32
solving all we get 98

Is this solution Helpfull? Yes (2) | No (1)  

THOTAPALLI SAIMOUNIKA  (9 years ago)

ans is 100
rajs age, r=32
before 8 years rajs age is (32-8) i,e.,24
rajs father age = r.f
after 4years, r.f= 2*(r+4) = 2*(24+4) = 56
rajs mother age=r.m
before 2 years, r.m=2*(r-2) = 2*(24-2) = 44
r.f + r.m = 100

Is this solution Helpfull? Yes | No (3)  

Lanka Sai Subramanyam  (8 years ago)

ans is 98

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Swati Jha  (8 years ago)

let present ages of raj his father and his mother be x,y and z respectively.
then (y+1)=2(x+4)...........(1)
(z-2)=2(x-2).............(2)
x+8=32........(3)
solving all three equations we get x=24 y=55 and z=46. so sum of his parents age=y+z=101

Is this solution Helpfull? Yes | No (1)  

RAJIV SINGH  (8 years ago)

after 8 years raj age is 32 so present age of raj is 24. according to question after 4 year raj age is 28 so father age is 56 and from 2nd part of question 2years ago raha age is 22 so mother age is 44 . so present mother is 46 and fathers age is 52 so sum of the age is 98

Is this solution Helpfull? Yes | No (1)  

Ayush AGarwal  (8 years ago)

R.F=RAJS FATHER AGE
R=RAJS AGE
R.M=RAJS MOTHER AGE

Raj age after 8 yrs 32
so 32-8 = 24 (8 yrs back from now)

Again, raj 24 + 4yrs =28 ( 4 yrs back from now)
that time R.F was 28*2= 56 (double of raj)
and R.M 2 yrs ago when raj was 24 she was ((24-2)*2)=44

now after 8 years R.F will be 56+4=60
and R.M will be 44+10=54 as 10 yrs back she was 44 from now
60+54 = 114

Is this solution Helpfull? Yes | No (2)  

D Nandini  (8 years ago)

lets take father age=f,son=r,mother=m
after 4 years f+4=2(r+4)
before 2 years r-2=2(m-2)
after 4 years r+8=32->r=24
substitute r=24 in eqn 1 and 2
you will get f=52,m=46
f+m=98

Is this solution Helpfull? Yes | No   

kirti gaur  (8 years ago)

answer is 100. it is given his current age is 32-8=24.
fathers age after four years will be twice his age. so father's age=(24+4)*2=56
mother's age was twice raj's age two years ago then mother's age=(24-2)*2=44
sum of parents age= 56+44=100

Is this solution Helpfull? Yes | No (2)  

Ankita Ghosh  (3 years ago)

Raj's present age=32-8=24.
Two years ago, his mother age=2*his age at that time=2*22=44.
therefore,his mother's age at present=44+2=46.
four years later, his father age=2*his age at that time=2*28=56.
therefore,his father's age at present=56-4=52.
hence, the sum of his parents age now is=46+52=98.

Is this solution Helpfull? Yes | No   

Saumya  (3 years ago)

Rf + 4 = 2(R+4) (1)
Rm - 2 = 2(R-2) (2)
after 8 years---
R+8 = 32
R = 24
on putting value of R in 1 and 2 we get-
Rf = 52, Rm = 46
therefore sum, 52+46 = 98

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