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(#M40011892) TCS question Keep an EYE

100 mtr race, A beats B by 15 mtr, B beats C by 10 mtrs, A beats C by 5 secs, speed of c?

Asked In TCS (11 years ago)

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Garima  (11 years ago)

4.7 mtrs/sec

100 mtr race, A beats B by 15 mtr,
means
when A covers 100m , B covers 85 mtrs
B beats C by 10 mtrs, when B covers 100 mtrs, C covers 90 m.
when B covers 85 mtrs, C covers 90*85/100 = 153/2 mtrs

so when A covers 100mtrs, B covers 85 mtrs, C covers 153/2 mtrs.
It means 100-153/2 = 47/2 mtrs are covers by C in 5 secs
so speed of C = 47/10 = 4.7 mtrs/sec

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BRIJESH KUMAR GUPTA  (11 years ago)

speed of c=4.7m/secr
let speed of a=20v then that of b=17v and solving speed of c=20v/(1+v)
again b beats c by 10 meter the time in which b travels 100 meter=100/17v
now [20v/(1+v)]*[100/17v]=90 solve it u will get 20v/(1+v)=4.7

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Archana   (11 years ago)

is the ans 5

Is this solution Helpfull? Yes (1) | No (8)  

mahalakshmi  (11 years ago)

post the options pls...

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