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(#M40011911) TCS question Keep an EYE

N=9+X+Y-Z, X,Y,Z(- 0-9, A wants to maximize and b wants 2 minimize, maximum value of N=? if A turns 1st...

Asked In TCS Arijit Roy (11 years ago)

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Gurdeep Singh bhatia  (11 years ago)

Ans is 20
X=6 or X=8 or X=5
Y=9 Y=9 Y=9
Z=4 Z=6 Z=3

using this strategy only we will get the optimal result!!!!!The whole strategy depends on the first no!!!!
If we choose a no bigger than 5 or 6 it will make N minimum.
If we choose a no smaller than 5 or 6, N will not be maximised.

and whatever no is chosen by A at the second time, B will have to put it in Z because if he wont, A will choose the last no as 0 and the varible Z will be of no use then

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prateek  (11 years ago)

ans= 18.

as A wnt to maximize so A always slct max no.(9)n B placed it on any variable like
fist in place of Z thn again A select 9 n B placed it on any variable....
so eq. become 9+9+9-9 = 18. ANS....

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Rituraj  (11 years ago)

check at
http://www.m4maths.com/416-alok-n-bhanu-play-the-following-min-max-game-N-9-X-Y-Z-so-wer-x-y-z-are-variables.html

Puzzle no
(#M40000416)

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gopal kumar  (11 years ago)

9+9=18
ans

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prachitrivedi  (11 years ago)

9+9+8-7=19

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shivesh  (11 years ago)

18 i suppose

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