Latest TCS Aptitude Question SOLUTION: 14. The number of 11 letter words formed by using English alphabets if all vowels are used such that no two vowels are adjacent to each other is: a. 5! * 20! / 15! b. 5! * 21! / 15

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14. The number of 11 letter words formed by using English alphabets if all vowels are used such that no two vowels are adjacent to each other is:
a. 5! * 20! / 15!
b. 5! * 21! / 15!
c. 21! / 10!
d. 21! / 15!

Asked In TCS rajendra prasad (9 years ago)

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shaikshabeena  (9 years ago)

Five vowels arranged alternatively in 5!ways nd in six gaps remaining 21 letters arranged in 21*20*19*18*17*16ways
So answer is 5!*(21!/15!)

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Souvik Jana  (7 years ago)

first arrange the 5 vowels in 5!
no of gaps to be filled to make a 11 letter word is 6. eg.. ___ A___ E ___ I ___ O ___ U__
no of gaps is 6
the 6 gaps can be filled in 21P6 ways (as 5 vowels are already used remaining letters are 21)
So total no of ways= 5!* 21P6
= 5!* (21!/15!) [that is option b]

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Abhijit Das  (9 years ago)

5!*20! /15!

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