Latest TCS Aptitude Question SOLUTION: Aditya has 35 computer files that he wants to store on floppy disks. Each floppy disk has a capacity of 1.44 megabytes (MB). 2 of the files have size 0.8MB, 16 have size 0.7MB and

• Placement Papers
• /
• TCS

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40011967) TCS question Keep an EYE

Aditya has 35 computer files that he wants to store on floppy disks. Each floppy disk has a capacity of 1.44 megabytes (MB). 2 of the files have size 0.8MB, 16 have size 0.7MB and the remaining 17 have size 0.4MB. No file can be split across floppy disks. What is the minimal number of floppy disks that will hold all these files?

16
18
14
15
17

Asked In TCS deepak gupta (11 years ago)

Solved Reema khan Read Solution (8)

Is this Puzzle helpful?   (33)   (7) Submit Your Solution

Read Solution (8) :

Reema khan  (11 years ago)

since no files can b split into two floppy disks
1st disk=.8+.4=1.2MB
2 such disks are required
3rd disk=.7*2=1.4MB
8 such disks are required
next disk=.4*3=1.2MB
5 such disks are required
hence total of 2+8+5=15 disks required (minimum)

Is this solution Helpfull? Yes (47) | No (1)  

Aditi   (11 years ago)

let A be the type of those two files having size 0.8MB
B type of files having size 0.7MB
C type of files having size 0.4MB
max capacity of 1 floppy is 1.44MB

now, for type B files we can save 2 files in 1 floppy ,coz .7+.7=1.4 if we try to add 3rd value will exceed the maximum capacity..hence we will save the next 2 files in next floppy..as from pattern we can say 1 floppy is required to save 2 files of type B..so total 8 floppy req. to save 16 files of type B.

now, for type C we can save 3 files in 1 floppy, coz .4+.4+.4 = 1.2, if we try to save 4th file value will agai exceed the max. capacity of floppy..similarly next 3 will be saved in 2nd floppy..and so on..as the total files of type C is 17, and we can save 3 files in 1 floppy so, 15 files can be saved in 5 floppy and 2 will be left..

now these 2 can be saved with the files of type A having size 0.8 MB

so, 0.8(1 file of type A)+0.4(1 file of type C) = 1.2
0.8(2nd file of type A) + 0.4(2nd file of type C) = 1.2
here in last condition we used 2 floppy

so, toal disks used are = 8+5+2 = 15

Is this solution Helpfull? Yes (28) | No   

aaron  (11 years ago)

ans is 15

Is this solution Helpfull? Yes (4) | No   

ravi tiwari  (11 years ago)

16 files of .7 mb takes 11.2mb and 2 files of .8mb takes 1.6 mb and 4 files of .4 mb takes 1.6mb so total space till now we use 11.2+1.6+1.6=14.4 mb means 10 floppy disks and now 13 .4mb files are left.. so for 13 files of .4 mb we require 13*.4=5.2mb space for which we require minimum 4 disks of 1.44mb so total minimum disk require =10+4=14

Is this solution Helpfull? Yes (3) | No (10)  

saurabh  (11 years ago)

total mb's=2*8 +16*.7+17*.4=19.6
numbr of dics=19.6/1.44=13.6
so 13 disc are cnfrm
storge in 13 discs=13*1.44=18.72
remaining mb's=19.6-18.72=.88
so for .88mb,we have to use 1 more disc..
so ans is 13+1=14discs

Is this solution Helpfull? Yes (2) | No (15)  

shilpa  (11 years ago)

its 15 or 14???????

Is this solution Helpfull? Yes (2) | No (2)  

niki  (11 years ago)

shouldnt d answer b 16 as remaining 17 files require 6 disks....

Is this solution Helpfull? Yes (1) | No (9)  

KATTA PRUDHVI GOUD  (7 years ago)

ans is 15
0.7*2=1.4 -------> 8 floppies
0.8+0.4=1.2 -----> 2 floppies
0.4*3=1.2 -------> 5 floppies
total = 8+2+5=15 floppies

Is this solution Helpfull? Yes (1) | No   

Please Login to Read Solution.