Latest TCS Aptitude Question SOLUTION: 4. A,B and C can do some work in 36 days.A and B together do twice as much work as C.A and C together do thrice as much work as B.Time taken by C alone to complete the work : (a)72

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4. A,B and C can do some work in 36 days.A and B together do twice as much work as C.A and C together do thrice as much work as B.Time taken by C alone to complete the work :
(a)72 (b)120 (c)96 (d)108

Asked In TCS Ashish Singh (11 years ago)

Unsolved Read Solution (14)

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Read Solution (14) :

saurabh  (11 years ago)

1/a +1/b +1/c =1/36..eq1
1/a +1/b =2/c ..eq2
1/a +1/c =3/b ..eq3
eq1-eq2
1/c =1/36 - 2/c
3/c =1/36
c=108...ans

Is this solution Helpfull? Yes (19) | No   

thiru  (11 years ago)

A+B+C=1/36 ...... 1
A+B=2C ........ 2
A+C=3B
sub 2 in 1
2C+C=1/36 therefore C=1/108 and hence 108 is d ans

Is this solution Helpfull? Yes (8) | No   

peddireddi sreelatha  (8 years ago)

1/a+1/b+1/c=1/36--->(1)
1/a+1/b=2/c--->(2)
1/a+1/c=3/b--->(3)
sub (2) in (1) , we get
3/c=1/36
c=36*3=108
ans is c=108

Is this solution Helpfull? Yes (1) | No   

shivam kumar sahu   (8 years ago)

1/a+1/b+1/c=1/36
1/a+1/b=2/c
1/a+1/c=3/c
now after solving above 2 equation
1/a=5/4c
1/b =3/4c
now
5/4c+3/4c+1/c=1/36
c=108

Is this solution Helpfull? Yes (1) | No   

gangesh  (8 years ago)

ans=108;
a+b+c=1/36 work per day .given that:a+b=2cand a+c=2b.put a+b=2c in a+b+c=1/36;
so c=1/108 work per day, so c complete in 108day;

Is this solution Helpfull? Yes (1) | No   

sagar rajaram rane  (8 years ago)

Let the equations turn out to be...

A+B+C=36......(1)
A+B=2C..........(2)
A+C=3B...........(3)

put eq (2) in eq (1)

2C+C=1/36
3C=1/36
C=108...

Is this solution Helpfull? Yes (1) | No   

k.loganayagi  (8 years ago)

A+B+C=1/36 ->eq1
A+B=2C ->eq2
A+C=3B ->eq3
eq2 in eq1
2C+C=1/36
3C=1/36
C=1/108..........ans is (d)

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volam chandan teja  (8 years ago)

by solving eqns we get 12b=36 which implies b can do work in 36*12 days and we get 4b=c so c can do same work in 36*12/4=108

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shatabdi mandal  (8 years ago)

answer will be 108.

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Sandeep Patidar  (8 years ago)

(1/a)+(1/b)+(1/c)=1/36
(1/a)+(1/b)=2/c
c=108 days

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Surekha N  (8 years ago)

1/A+1/B+1/C=1/36...Eq.(1)
1/A+1/B=1/2C...Eq.(2)
1/A+1/C=1/3B
Substitute Eq.(1) in Eq.(2)
Then we can find that C can complete the work in 108 days...
then 1/2C+1/C

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rohit  (8 years ago)

108....a+b +c-1/36
a+b-2c....equation 1
a+c-3b .... equation 2 getting d values of a and c
put in equation a+b+c=1/36

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Harish  (8 years ago)

option d..as a+b=2c; time and work are inversly proportional....let c can do the work in 2x days and a+b can do the work in x days. we know a+b+c=36 days ...one day work of a+b+c=1/36;one day work of a+b=1/x;c=1/2x;a+b+c=1/36;(1/2x)+(1/x)=1/36;then x=54......by this 108

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arpit batri  (8 years ago)

Very simple-
1/a+1/b+1/c=1/36 -eqn 1
1/a+1/b=2/c -eqn 2
1/a+1/c=3/c (no use)
now after equating eqn2 in eqn1, we have
2/c+1/c=1/36
On furthure solving,
3/c = 1/36
So, c = 3*36
C=108

No need of equation 2

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