Latest TCS Aptitude Question SOLUTION: 7. x takes 4 days to complete one third of a job, y takes 3 days to complete one sixth of the Same job and z takes 5 days

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7. x takes 4 days to complete one third of a job, y takes 3 days to complete one sixth of the
Same job and z takes 5 days to complete half of the job.If all of them work together for 3 days and x and z quit, how long will it take for y to complete the remaining work done?

Asked In TCS Arit (11 years ago)

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Sri Harsha  (11 years ago)

x takes 4*3=12 days to complete the job=> work done in 1 day=1/12
y takes3*6=18 days to complete the job=> work done in 1 day=1/18
z takes 5*2=10 days to complete the job=> work done in 1 day=1/10
Work done by all of them in 3 days=3*(1/12+1/18+1/10)
=3*(15+10+18)/180
=43/60
work left=17/60
if y takes a days,
work done=a*1/18=17/60
=>a=(17*18)/60
=>a=5.1 days

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MP   (11 years ago)

x takes 4 days to complete one third of a job, y takes 3 days to complete one sixth of the
Same job and z takes 5 days to complete half of the job.
x takes 12 days to complete a job, y takes 18 days to complete the
Same job and z takes 10 days to complete the job.

3 days job when they work together = 3*( 1/12 = 1/18 + 1/10) = 43/60
Balance work (17/60) is done by Y in 18*17/60 = 51/10 = 5.1 days

Is this solution Helpfull? Yes (6) | No (2)  

anusha  (11 years ago)

work done by x in 1day=1/12
work done by y in 1day=1/18
work done by z in 1day=1/10 LCM of 12,18,10 is 180.
so,x does =>1/12*180=15,y does=>1/18*180=10,z does =>1/10*180=18
work done by x,y,z in 1day=15+10+18=43
work done by x,y,z in 3day=3*43=129 after 3 days x and z quit so,
remaining work=180-129=51
work done by y in 1day=10
so y complete the work in 5.1days

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Koushik Pal  (11 years ago)

X=>4*3=12
Y=>6*3=18
Z=>5*2=10
3*(1/12+1/18+1/10)+remain/18=1
(Formula: A did/A can + B did/B can=1)
(Here,3(1/X can+1/Y can+1/Z can)+remain/Y can=1)
remain=5.1

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