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(#M40121966) IBM Numerical Ability question Number Keep an EYE

Tell me..how to find no.of zeros in 50!

Asked In IBM Roopam Shukla (10 years ago)

Unsolved Read Solution (3)

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chandana  (10 years ago)

Divide by 5: 50/5-->10
Divide by 5^2: 50/25-->2
Sum all the divisions: 10+2=12
number of zeros up to 50! = 12

Is this solution Helpfull? Yes (15) | No   

Prakash Singh  (10 years ago)

we have to count occurrence of digit 5 in the given factorial to count the number of zeros.
for example: in 50! we have
5,10,15,20,25,30,35,40,45,50 these many multiples of 5.

for 25 we have 5*5: count is 2
same is for 50- 5*5*2 :count is 2
for others count is 1. so total count of 5 is 12. this is the answer

Is this solution Helpfull? Yes (3) | No (4)  

uttam kumar  (8 years ago)

formula for no of zeros
n/5+n/5^2+n/5^3+....and so on ,we count only integaral value ...here we have to find no of zeros in 50
50/5+50/5^2+50/5^3+....=10+2=12 answer because we will not count 50/5^3 as integral value.

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