Latest TCS Aptitude Question SOLUTION: Each of A,B and C need a certain unique time to do certain work. C needs 1 hour less than A to complete the work. Working together they require 30 minutes to complete 50% of the wo

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Time and Work

TCS Question Papers: TCS Interview Experience(90) TCS Company Profile

(#M40012211) TCS Numerical Ability question Keep an EYE

Each of A,B and C need a
certain unique time to do certain work. C needs 1 hour less than A
to complete the work. Working together they require 30 minutes to
complete 50% of the work. The work also gets completed if A and B
start working together and A leaves after 1 hour and B works further
3 hours. How much work does C do per hour?
a. 16.66%
b. 66.66%
c. 50%
d. 33.33%

Asked In TCS kanika (11 years ago)

Unsolved Read Solution (8)

Is this Puzzle helpful?   (32)   (26) Submit Your Solution Time and Work

Read Solution (8) :

BALENDU NARAIN PANDEY  (11 years ago)

50% suppose A do work in x hrs ,B in y, then c would do in x-1 hrs..then 1/x+1/x-1+1/y=1 in 1 hrs..also A&B 1 hrs work 1/x+1/y then work remaining xy-x-y/xy which is done by B in 3 hrs so (xy-x-y)/xy=3/y it results y=4x/x-1 putting value we get x=3 so y=6 so A CAN DO WORK in 3 hrs B in 6 hrs & C IN 2 hrs that is 50%

Is this solution Helpfull? Yes (16) | No (8)  

MOHIBULLAH KHAN  (11 years ago)

50 % work done by c per hour

Is this solution Helpfull? Yes (3) | No (14)  

ashish kumar  (11 years ago)

correct ans will be 61.7%...dere is sme mistake in d option

Is this solution Helpfull? Yes (3) | No (11)  

Anubhav Kumar  (11 years ago)

@mohibullah plz explain..!

Is this solution Helpfull? Yes (2) | No (4)  

Rishika terala  (6 years ago)

Let A take 'a' hours to complete the work alone.
Then C takes (a-1) hours to complete the work alone.
In 1 hour 'A' completes 1/a of the work.
In 1 hour 'C' completes 1/(a-1) of the work.
Both together complete 1/a + 1/(a-1) = (2a-1)/a(a-1) of the work in 1 hour.
A & C together need a(a-1)/(2a-1) hours to complete the work.
Now A & C together complete 50% of work in 30 minutes
So A & C together complete 100% work in 1 hour.
Therefore a(a-1)/(2a-1) = 1
solving, a= {3(+/-)√(5)}/2
C takes one hour less than A to complete the work, which can not be -ve. So we can discard a=(3 - √5)/2 .
Hence a=(3 + √5)/2 .
So 'C' takes (a-1) = (1+√5 )/2 hours to complete the work.
In one hour 'C' will complete 2/(1+√5 ) = 2/3.24 = 0.66 of work
= 66%

Is this solution Helpfull? Yes (2) | No (2)  

Aparna Sutar  (11 years ago)

plz explain...

Is this solution Helpfull? Yes (1) | No (6)  

goldy  (11 years ago)

@ASHISH right 61.8%

Is this solution Helpfull? Yes | No (6)  

Sumit Biswas  (11 years ago)

balendu narain pandey
u cannt assume they together did the work in 1 hr.u r wrong

Is this solution Helpfull? Yes | No (6)  

Please Login to Read Solution.