Latest HCL Aptitude Question SOLUTION: One young and one old man reach a same distance in 20min and 30min respectively. If old starts at 10.00am and youngman starts at 10.05am. When they meet. Pls provide solution

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One young and one old man reach a same distance in 20min and 30min respectively. If old starts at 10.00am and youngman starts at 10.05am. When they meet. Pls provide solution

Asked In HCL Roopam Shukla (9 years ago)

Unsolved Read Solution (7)

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Read Solution (7) :

aman  (9 years ago)

The real ans is 10:15am
Explanation
Let the dis be 30 m
Old man travel 1m/min
Young travel 1.5m/min

At 10:05 old man = 5m
young = 0m
At 10:10 old man = 10m
young = 7.5m
At 10:15 old man= 15m
young = 15m

Is this solution Helpfull? Yes (22) | No (1)  

Reena  (8 years ago)

30 mins of old man=20 min of young man=same dist
15 min of old man=10 min of young man=same dist
Old man starts at 10.00 whereas young man starts at 10.05.
Thus at 10.15 young will catch up the old

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abhe chandu  (9 years ago)

can anyone explain the answer properly please.............?

Is this solution Helpfull? Yes (3) | No (1)  

NEHA TRIPATHI  (9 years ago)

at 10.06 am.

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smita kumari  (9 years ago)

At 10.12 am

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IMTIAZ AHMAD  (9 years ago)

let distance in meter, for 20 min 10 m and 30 min 10 m , when younger start, old man reached at 1.65 m distance, after that both walking and meet at 10:14 .

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sai kumar  (8 years ago)

the correct answer is 10.14
take the lcm of 20.30 and consider it as distance it is 60
for applying relative speed make the two stations time equal which is 10.05
at 10.05 the older one gets the distance 15m front then the remaining distance is 45m for 10.10 the younger one and older moves the distance 25 and the remaining distance is 20 then for 4 miutes the older one moves for 12m and the youger moves to another 8m so at 10.14 they will meet

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