Latest TCS Aptitude Question SOLUTION: In a triangle ABC, the lengths of the sides AB and AC equal 17.5 cm and 9 cm respectively. Let D be a point on the line segment BC such that AD is perpendicular to BC. If AD = 3 cm

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(#M40012324) TCS question Keep an EYE

In a triangle ABC, the lengths of the sides AB and AC equal 17.5 cm and 9 cm respectively. Let D be a point on the line segment BC such that AD is perpendicular to BC. If AD = 3 cm, then what is the
radius (in cm) of the circle circumscribing the triangle ABC?
A. 17.05 B. 27.85 C. 22.45 D. 32.25 E. 26.25

Asked In TCS (12 years ago)

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Dharun Kumar  (10 years ago)

circum radius = R
Area of the triangle ABC = Δ = ½ (BC)(AD) = ½ (a)(3) = 3a/2
The formula here is : R = abc/4Δ = abc / 4(3a/2) = bc/6 = (17.5)(9)/6 = 26.25

Is this solution Helpfull? Yes (29) | No (2)  

goldy  (12 years ago)

draw the diagrm:
AC=9,AB=17.5,AD=3
THEN from property CD=8.48
FROM A THEORM OF X STANDARD
(AD)^2=CD*DB
THUS DB=1.06
NOW R=abc/4*area
area=14.31
abc=1502.55
thus R=26.25

Is this solution Helpfull? Yes (21) | No (12)  

vikas  (12 years ago)

@goldyy how DB= 1.06,IF U USE PYTHAGORAS,BD COMES OUT TO BE 17.24,AS AB^2-AD^2=BD^2= 17.24

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jitendra birla  (12 years ago)

Area of a triangle = , where a, b and c are lengths of the sides of the triangle and R is the radius of the circle circumscribing the triangle

In this example, area of the triangle =

The area of any triangle can also be expressed as , as the altitude AD to the side BC is 3 cms.

Equating the two and solving for R, we get R = 26.25 cms

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Pawan Ahuja  (12 years ago)

@ goldy from where abc comes ?

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amar  (7 years ago)

Ans=26.25
Draw atriangle a,b,c points
BC=a, AC=b, AB=c;
AB=c=17.5; AC=b=9; BC=a;
Height=AD=3; to find circum of triangle=R
area of triangleABC=1/2(BC)(AD)=1/2(a)(3)=3a/2
R=abc/4xarea of triangle
R=abc/4(3a/2)=bc/6=(17.5)(9)/6=26.25

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