Latest TCS Aptitude Question SOLUTION: A,B and C can do a piece of work alone in 15 , 25 and 40 days respectively.They start together but B left the work as soon as the work was half completed and c left the work when

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A,B and C can do a piece of work alone in 15 , 25 and 40 days respectively.They start together but B left the work as soon as the work was half completed and c left the work when it was 3/4th completed. A doing the remaining work alone. In how many days the work completed?

Asked In TCS madhavi (12 years ago)

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prachitrivedi  (12 years ago)

ans 300/79+30/11+15/4=10.2747 days

Is this solution Helpfull? Yes (30) | No (3)  

goldy  (12 years ago)

ans will be 10.2742 days

Is this solution Helpfull? Yes (7) | No (1)  

srikhakollu bharghav  (12 years ago)

9.85 days...say nearly 10 days...madhavi...is it correct ???

Is this solution Helpfull? Yes (4) | No (7)  

Atul  (12 years ago)

8.5486 say 8.55 days.
total days = 300/79+30/11 + 15/4= 8.5486 days

Is this solution Helpfull? Yes (2) | No (7)  

Anubhav Kumar  (12 years ago)

its coming out to be 9.49 i.e. on 10th day work will be completed.

Is this solution Helpfull? Yes (2) | No (10)  

rajkumardubey  (12 years ago)

10.27 is correct answer................

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niki  (12 years ago)

pls explain the method... how it is solved?

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akriti gupta  (12 years ago)

plz mail me tcs new pattern paper akritigupta.2009@gmail.com

Is this solution Helpfull? Yes | No (3)  

ALLA RAKHI  (11 years ago)

ans:9.57 days
Take the L.C.M of 15,25,40 i.e 600 (assume this as total quantity of work to be done)
A completes 600/15= 40 units/day
B -> 600/25 =24
C-> 600/40=15
A+B+C together completes 79 units of work per day
Now, 300/79+( 150/(15+40))+150/40 =9.75 days approximately

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