Latest TCS Aptitude Question SOLUTION: 1st 44 int are written in order to form large no. N=123456............424344. What is the remainder when N is divided by 45?

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1st 44 int are written in order to form large no. N=123456............424344. What is the remainder when N is divided by 45?

Asked In TCS rathika (12 years ago)

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Sandeep singh  (12 years ago)

12345.....424344 = (1234...424290) + (54)
1st part is completly divisble by 45 and aftr dividng 54 by 45 we get 9 remaindr
remainder is = 9

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Utkarsh Kr  (11 years ago)

When we add digits from 1+2+3+4.....9 = 45
Now add digits 1+0+1+1+1+2+1+3......1+9 = 10+45 = 55
Now add digits 2+0+2+1+2+2+2+3......2+9 = 20+45 = 65
Now add digits 3+0+3+1+3+2+3+3......3+9 = 30+45 = 75
Now add digits 4+0+4+1+4+2+4+3+4+4 = 4*5+10 = 30
Now add 75+65+55+45+30 = 270
Factors of 45 are 5 and 9
270 is divisible by 9 ...... Hence if we divide the quotient ,got by dividing by 9 by 5 we will get , Answer as 4 .....

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teena  (12 years ago)

plz explain...how the first part is divisible by 45

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rathika  (12 years ago)

just 45*2=90 splited as (90+54=144)

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sahitya  (10 years ago)

We dint get any remainder....

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