Latest Capgemini Aptitude Question SOLUTION: 2.How many 4 digit no. can b formed wit digits 1, 2, 3,4,5 which r divisible by 4 and digits not repeated 144 / 168 / 182 / none 3.. If 1= (3/4)(1+ (y/x) ) then i. x=3y ii. x=y/3 i

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2.How many 4 digit no. can b formed wit digits 1, 2, 3,4,5 which r divisible by 4 and digits not repeated
144 / 168 / 182 / none
3.. If 1= (3/4)(1+ (y/x) ) then
i. x=3y
ii. x=y/3
iii. x=(2/3)y
iv. none

Asked In Capgemini (11 years ago)

Unsolved Read Solution (11)

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Read Solution (11) :

Arneet  (11 years ago)

last 2 digits can be 12,24,32,52 only.

First two numbers can be any two numbers of balance 3 numbers available.

so number of possible nos = 4*3*2 = 24

Is this solution Helpfull? Yes (20) | No (9)  

sridevi  (11 years ago)

2)a num div by 4 means last two digits should be either 12,24,32,52 which is possible in 4 ways. remaining 2 digits can be filled with remaining 3 digits in 6 ways.so,6*4=24 is the ans.

3)1=3/4(1+x/y)
x=3/4(x+y)
4x=3x+3y
x=3y
so option i

Is this solution Helpfull? Yes (7) | No (1)  

ravindra joshi  (11 years ago)

possible no's for last 2 digits are 12,24,32,52
so last 2 digits can be filled in 4! ways= 24 ways
now remaing 2 places can be filled in 3P2 ways= 3!=6
therefore final answer is = 6*24=144

Is this solution Helpfull? Yes (5) | No (14)  

gautam kumar sharma  (11 years ago)

24 is d answer

Is this solution Helpfull? Yes (3) | No (2)  

gauri dhale  (8 years ago)

1.none
2.i i.e x=3y

Is this solution Helpfull? Yes (3) | No (1)  

snehil  (11 years ago)

last tow digits make constent
now 2 place remaining
5 digit can arrang in 2 place with out repeat 2^4
now only 12 n 24 can be at last place so ans will be
2*2^4

Is this solution Helpfull? Yes (1) | No (1)  

Sandeep singh  (11 years ago)

The condition for any number to be divisible by 4 is that the last two digits taken together must be a multiple of 4
The digits given are - 1,2,3,4,.5
Now the last two digits must be a multiple of 4
There are 4 cases : 12 , 24 , 32 , 52 . So if the last two digits are these numbers then the five digit number formed would be divisible by 4

(a) If the last two digits are 12 , then the remaining 2 places can be filled in 2! ways
(b) if the last two digits are 24 , then the remaining 2 places can be filled in 2! ways
(c) if the last two digits are 32 , then the remaining 2 places can be filled in 2! ways
(d) if the last two digits are 52 , then the remaining 2 places can be filled in 2! ways

Total numbers which are divisible by 4 = 4*2!=8

Is this solution Helpfull? Yes (1) | No (8)  

Shruthi  (7 years ago)

If x=3y,then
1=(3/4)[1+(y/x)]
1=(3/4)(1+y/3y)
1=(3/4)(1+1/3)
1=(3/4)(4/3)
1=1
Hence ans is 3y

Is this solution Helpfull? Yes (1) | No   

jatin  (6 years ago)

ending 2 digits can be 12,24,32,52
fixing last two digits one by one
12-->3*2*1*1=6
24-->3*2*1*1=6
32-->3*2*1*1=6
52-->3*2*1*1=6
6+6+6+6=24
answer=24

Is this solution Helpfull? Yes (1) | No   

vishnu priya vellanki  (11 years ago)

4digit numbers=3!*2C1=12

Is this solution Helpfull? Yes | No (5)  

krishna mohan reddy  (8 years ago)

hiii this is good answer

Is this solution Helpfull? Yes | No (1)  

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