Latest TCS Aptitude Question SOLUTION: A hare and a tortoise race along a circle of 100 yards diameter. The tortoise goes in one direction and the hare in the other. The hare starts after tortoise has covered 1/5 of its

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A hare and a tortoise race along a circle of 100 yards diameter. The tortoise goes in one direction and the hare in the other. The hare starts after tortoise has covered 1/5 of its distance and that too leisurely. The hare and tortoise meet when the hare has covered only 1/8 of the distance. By what factor should the hare increase its speed so as to tie the race?
(a)8
(b) 37.80
(c) 40
(d) 5

Asked In TCS shilpa (11 years ago)

Unsolved Read Solution (5)

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Read Solution (5) :

Garima  (11 years ago)

After tortoise covers 1/5th distance hare starts the race
When hare covers 1/8th of distance tortoise meets hare
So distance covered by tortoise = 1-(1/5 + 1/8)
= 27/40
Time taken by both is same
time = dist/speed
So (dist covered by tortoise/ speed of tortoise) = (dist covered by hare / speed of hare)
let speed of tortoise be t and speed of hare be h
27/40t = 1/8h
h = (40/(8*27) )* t = 5/27 * t which is initial speed of hare
Now for the next part hare has to cover 7/8 th distance when tortoise covers 1/8 th distance
so we get
1/8t = 7/8h
h = 7t which is final speed of hare
so the factor by which hare's speed should increase = 7t/ (5/27 * t)= 189/5
= 37.8

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Garima  (11 years ago)

hare increase its speed 37.80 times so as to tie the race.

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SHANU MAHAJAN  (11 years ago)

garima pls explain the 2nd part. 1/8t = 7/8h
h = 7t which is final speed of hare.
does tie up means vice versa of distance travelled by them. becoz for hare it was 1/8 now you took 1/8 for tortoise.

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sagar  (11 years ago)

Garima how can u say the distance covered by tortoise is 27/40
.

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ryan  (11 years ago)

hare has to increase his speed by 37.80 times

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