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(#M40012900) TCS question Keep an EYE

if m+n is diveded by 12 then remainder is 8 and m-n diveded by 12 them remainder is 6 mn is diveded by 6 then remainder is?

Asked In TCS poonam rajak (12 years ago)

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Lakshman Devrari  (12 years ago)

if m+n is divided by 12 then remainder is 8
so m+n = 12x+8
and m-n divided by 12, remainder is 6
so
m-n= 12y+6

From these 2 equations, we get
m= 6(x+y)+7
n= 12(x+y)+1
put x+y=k, then
mn = (6k+7)*(6k+1) = 36 k^2+48k+6+1
or
6(6k^2+8k+1)+1

when mn is divided by 6, remainder will be 1 as first terms in expression of mn are multiple of 6...:)

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Garima  (12 years ago)

if m+n is divided by 12 then remainder is 8
so m+n = 12x+8
and m-n divided by 12, remainder is 6
so
m-n= 12y+6

From these 2 equations, we get
m= 6(x+y)+7
n= 12(x+y)+1
put x+y=k, then
mn = (6k+7)*(6k+1) = 36 k^2+48k+7

when mn is divided by 12, remainder will be 7 as first two terms in expression of mn are multiple of 12.

so remainder is 7.

Is this solution Helpfull? Yes (2) | No (8)  

rani.m  (12 years ago)

(m+n)2-(m-n)2=4mn
(8)2-(6)2=4mn
24=4mn
mn=7
but we divide mn by 6 then mn becomes double
remainder is 7*2=14

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