Latest Elitmus Aptitude Question SOLUTION: find the number of terms between 100 to 1000…..in the format like 234 2*3*4=24…..find the number of term whose multiple is 24

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(#M40013202) ELITMUS Numerical Ability question Keep an EYE

find the number of terms between 100 to 1000…..in the format
like 234
2*3*4=24…..find the number of term whose multiple is 24

Asked In Elitmus CHARANJEET (12 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

sanjog kumar  (12 years ago)

138=24,146=24,164=24,183=24
226=24,234=24,243=24,262=24
318=24,324=24,342=24,381=24
416=24,423=24,432=24,461=24
614=24,622=24,641=24
813=24,831=24
answer=21

Is this solution Helpfull? Yes (59) | No (3)  

suvadip rang  (11 years ago)

A product of 24 can be achieved by (1,3,8), (1,4,6), (2,2,6), (2,3,4)
Now these numbers can be arranged in 3! ways respectively
However 2,2,6 can be arranged in 3!/2! ways
Hence, the answer is 3*3! + 1*3!/2! = 18+3 = 21

Is this solution Helpfull? Yes (51) | No   

shruti  (12 years ago)

243: 2*3*4=24
324: 3*2*4=24
342: 3*4*2=24
423: 4*2*3=24
432: 4*3*2=24
226: 2*2*6=24
262: 2*6*2=24
622: 6*2*2=24

Is this solution Helpfull? Yes (6) | No (8)  

Suparna Das  (12 years ago)

th of digits can be 1,4,6 or 8,1,3 or 2,2,6 or 2,3,4.each can b arranged in 3 ways..
so 4 combinations in 3 ways
so 4*3=12

Is this solution Helpfull? Yes (4) | No (3)  

akanki agrawal  (10 years ago)

138,183,318,381,813,831
146,164,416,461,614,641
243,234,423,432,324,342
262,622,226
therfore ans is 21

Is this solution Helpfull? Yes (2) | No   

Mohit  (9 years ago)

234, 243, 324, 342, 432, 423= 6 ways
so,
164= 6 ways
813= 6 ways
and
226= 3 ways
i.e 21 ways.

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jayavardhan  (12 years ago)

234=2*3*4=24
243
324
342
423
432
226
262
622

Is this solution Helpfull? Yes (1) | No (3)  

Swaraj Behera  (12 years ago)

th of digits can be 1,4,6 or 8,1,3 or 2,2,6 or 2,3,4.each can b arranged in 3 ways..
so 4 combinations in 3 ways
so 4*3=12

Is this solution Helpfull? Yes (1) | No (3)  

SHUBHAM  (4 years ago)

answer should be 262 , taking hundreds as an even number,we get: ( 843,826,846,866,883,886,889,849) ,(643,626,646,666,683,686,689,649),(443,.......),(243,...) and for odd nos : (138,168,164,198),(338,368,364,398),(538,..),(738,...),(938,...)
total possible combinations= 148(from even) + 114(from odd) =262

please notify me if I'm doing it wrong

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avinash kumar  (9 years ago)

234,164 &183 can be arranged in 6 ways and 226 can be arranged in 3 ways
hence 6+6+6+3=21

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