Latest TCS Aptitude Question SOLUTION: 1,7,8,49,50,56,57,343,344,350,351,392,393,399,400 The above sequence contains sum of distinct power of 7 in increasing order(7^0,7^1,7^1+7^0,7^2 etc.) What is value of term number

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1,7,8,49,50,56,57,343,344,350,351,392,393,399,400
The above sequence contains sum of distinct power of 7 in increasing order(7^0,7^1,7^1+7^0,7^2 etc.) What is value of term number 38 ?

Asked In TCS vaibhav agarwal (11 years ago)

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Akshay jain  (11 years ago)

2nd term is 7^1
4th term is 7^2
8th term is 7^3
so 16th term will be 7^4 and 32nd=7^5
now as we see 3rd term=7+1
5th term=49+1
6th term=49+7
7th term=49+8
now,9th term=343+1
10th=343+7
11th=343+8
12th=343+49 and so on..
so, 33rd term=(7^5)+1=16808
34th=16807+7
35th=16807+8
38th=16807+56=16863 (ans)

Is this solution Helpfull? Yes (26) | No (17)  

swati singh  (11 years ago)

akshay your soloution is wrong..clear your basics dont mislead..
in these type of questions there is a trick
as shown is series it is like
7^0
7^1
7^0+7^1
7^2
7^0+7^2
7^1+7^2
.....
hence last term in power five will be
7^5+7^4+7^3+7^2+7^1+7^0 this is first method
now second method is trick based that is we want 38 term directly solve like this
so first number is 3 and second is 8 so gap is 8-3=5 when we calculate this polynomial hence ans is 7^3+7^5=17150..

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swati singh  (11 years ago)

@akshay shut up and mind your language..

Is this solution Helpfull? Yes (6) | No (7)  

Akshay jain  (11 years ago)

@swati first see your language then tell me anything...so you shut up..

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Panna Lal Patodia  (11 years ago)

It is very simple. Convert the number to binary. For example 5 = 101 in binary. So, the 5th term is 7^2 + 7^0 = 50 ignoring zeros of binary numbers. Another example 10 = 1010 in binary. So, the 10th term is 7^3 + 7^1 = 350. Now, 38 = 100110 in binary. So, 38th term = 7^5 + 7^2 + 7^1 = 16863.

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Prasanth G Krishna  (11 years ago)

clearly we have pattern here.... the power term positions follow like
for 38th value split it in the powers of 2 like
38 = 32+6
32+4+2
then write as 2^5+2^2+2^0

then just replace the 2 base with 7 number given that leads us to

=7^5+7^2+7^0
=16807+49+1
=16857

now we can do this method for any value series

Is this solution Helpfull? Yes (5) | No (1)  

Akshay jain  (11 years ago)

@ SWATI SINGH
give your answer if u want dont judge anyone's answer...
now i have given it with logic..

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Honey  (11 years ago)

answer is 7^5+7^2+7^1=16863

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sameera saxena  (11 years ago)

akshay jain can u please explain how??

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shivani garg  (11 years ago)

ans -16863

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Akshay jain  (11 years ago)

ans is=16978

Is this solution Helpfull? Yes (1) | No (9)  

ROJA KUMARI  (11 years ago)

the 38th term will be 7^3+7^7=823886

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Shiva  (11 years ago)

please send it today at sobhandutta@gmail.com

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  (4 years ago)

In PRASANTH G KRISHNA solution I made the correction.

clearly we have pattern here.... the power term positions follow like
for 38th value split it in the powers of 2 like
38 = 32+6
32+4+2
then write as 2^5+2^2+2^1

then just replace the 2 base with 7 number given that leads us to

=7^5+7^2+7^1
=16807+49+7
=16863

now we can do this method for any value series

Is this solution Helpfull? Yes | No   

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