Latest exam Aptitude Question SOLUTION: (-j)^3 * (-j^9)^4 over (j^3)^5

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Previous Question: Determine the sum for the geometric series 1/2 - 1/3 + 2/9 - 4/27 +... Next Question: I need to completely factor 100-x^2y^2 and I came up with (50-xy)(50+xy). Is this correct?

(#M40135717) EXAM Numerical Ability question Keep an EYE

(-j)^3 * (-j^9)^4 over (j^3)^5: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: Determine the sum for the geometric series 1/2 - 1/3 + 2/9 - 4/27 +... Next Question: I need to completely factor 100-x^2y^2 and I came up with (50-xy)(50+xy). Is this correct?

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