• Placement Papers
• /
• self
• /
• Numerical Ability
• /
• Number System

self Question Papers:

(#M40013581) SELF Numerical Ability question Keep an EYE

Find the consecutive zeros at the end of the following numbers?
1)72!
2)57*60*30*15625*4096*625*875*975

Prasad (12 years ago)

Unsolved Read Solution (1)

Is this Puzzle helpful?   (8)   (4) Submit Your Solution Number System

Read Solution (1) :

Aman  (12 years ago)

consecutive zeros at the end of 72! = 72/5 +72/25 = 14+2=16

consecutive zeros at the end of 57*60*30*15625*4096*625*875*975=
consecutive zeros at the end of 10*2*3*3*10*5^6*2^12*5^4*7*5^3*39*5^2 =
consecutive zeros at the end of 10*2*10*5^6*2^12*5^4*5^3*5^2=
consecutive zeros at the end of 10^2 *(2^13)*(5^13)=
consecutive zeros at the end of (10^2)*(10^13) = 15 zeros

Is this solution Helpfull? Yes (5) | No   

Please Login to Read Solution.