Latest self Aptitude Question SOLUTION: 3AB=DE 5BC=LM 7CD=??

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(#M40013646) SELF question What comes in place of ?? Keep an EYE

3AB=DE
5BC=LM
7CD=??

Devendra Marghade (11 years ago)

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Math Lovers  (11 years ago)

7CD = XY

e>xplanation-
3AB = DE => 3,1,2 = 4,5
5BC = LM => 5,2,3 = 12, 13
We can observe,first number of RHS = first number of LHS * first number eqv to digit + first number eqv to digit
similarly,
second number of RHS = first number of LHS * first number eqv to digit + Second number eqv to digit
so,
7CD = 7*3+3,7*3+4 = 24, 25 = XY

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Rajesh Kumar Sethi  (11 years ago)

Answer is TU

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PANKAJ  (11 years ago)

ANSWER IS XY.
AS EXPLAINED BY CHANDAN...

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ashfaque ahmed  (11 years ago)

7CD=XY

3AB=3*(1+2)=9=(4+5)=DE
5BC=5*(2+3)=25=(12+13)=LM
7CD=7*(3+4)=49=(24+25)=XY

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Rajesh Kumar Sethi  (11 years ago)

Answer is TU
solution:
let A = 1 B = 2 C = 3 and so on...........
now see the L.H.S the numbers are increasing in a perticular sequence.
then see the second and third, the alphabets are also increasing in a perticular sequnce.
Now see the R.H.S
Like LHS the letters must increase with a perticular sequence
i.e. value of L = 12 and value of D = 4. so L - D = 12 - 4 = 8
=>(value of L)+8 = 20 = T
then, value of M = 13 and value of E = 5. so M - E = 8
=>(value of M) + 8= 21 = U
so the answer is TU

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