Latest Elitmus Aptitude Question SOLUTION: Eden park is a cricket field while jubilee park is a football field in Mastnagar,all cricket fields are circular and football fields are rectangular of square.along the boundary of

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(#M40013678) ELITMUS Numerical Ability question geometry Keep an EYE

Eden park is a cricket field while jubilee park is a football field in Mastnagar,all cricket fields are circular and football fields are rectangular of square.along the boundary of all fields there are advertisement displays.in mastnagar,the length of advertisement displays has to be same across all playing fields.Area of jubliee park is 468 sqm.the farthest distance between any two points in jubliee park football field is 10*(1.43)m.find the approximate area of eden park?

Asked In Elitmus Swaraj Behera (11 years ago)

Unsolved Read Solution (7)

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Garima  (11 years ago)

If Area of jubliee park is 468 sqm.the farthest distance between any two points in jubliee park football field is 10sqrt(10),
and l and b are length and breadth of rectangular park, then
l^2+b^2 = (10sqrt(10))^2= 1000
l*b = 468 sq mtrs
(l+b)^2= 1000+2*468=1936
l+b=44
perimeter of rectangle= perimeter of circular field of Eden park = 2*44=88 mtrs
radius of eden park = 88/2*pi= 44*7/22= 14 mtrs
Area of eden park = Pi*r^2 = 14*14*22/7 = 44*14 = 616 sq mtrs

Is this solution Helpfull? Yes (63) | No (6)  

siddharth prakash singh  (9 years ago)

Let us consider the football field to be rectangular with dimensions L* B. if the

football field is square then we will get L = B.

Given Area of jubilee park = 468 sqm.

so, area of rect. park = LxB = 468 …… (i)

Farthest distance of field is diagonal ;

Therefore length of diagonal ; D = sqrt(L^2+B^2) = 10√10

or L2+B2 = 1000 …….. (ii)

Therefore; (L + B)^2= L^2+B^2 + 2LB = 1000 + 2 * 468 = 1936

or , (L+B) = Sqrt(1936) = 44

Perimeter of rect. Field = 2 (L + B) = 2 * 44 = 88m

since Perimeter of rectangular field = Circumference of Circular field

therefore, Circumference of Circular field = 2*pi*R = 88m

Radius of circular field = 14m

Therefore Area of circular field = 142pi = 616 sqm

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Mihir  (11 years ago)

I think given data is wrong.
In rectanglular field, area = length*breadth = 468 sq m

At least one side is more than 21 mtrs .
whereas the farthest distance between any two points in jubliee park football field is 10*(1.43)m ( given ).
so given data is incorrect.

Is this solution Helpfull? Yes (5) | No (10)  

Swaraj Behera  (11 years ago)

that is 10sqrt(10)...now tell me the answ??

Is this solution Helpfull? Yes (2) | No (6)  

sachin  (11 years ago)

mihir check this

length * breath = 18*26 = 468
and
(10sqrt(10))^2 = length^2 + breath^2
1000 = 18^2 + 26^2

Is this solution Helpfull? Yes (1) | No (3)  

vikram singh  (7 years ago)

mr. swaraj why did write 1.43 instead of sqrt(10).
what is nonsense . totaly time disturb

Is this solution Helpfull? Yes (1) | No (1)  

Aashul Tiwari  (5 years ago)

If Area of jubliee park is 468 sqm.the farthest distance between any two points in jubliee park football field is 10sqrt(10),
and l and b are length and breadth of rectangular park, then
l^2+b^2 = (10sqrt(10))^2= 1000
l*b = 468 sq mtrs
(l+b)^2= 1000+2*468=1936
l+b=44
perimeter of rectangle= perimeter of circular field of Eden park = 2*44=88 mtrs
radius of eden park = 88/2*pi= 44*7/22= 14 mtrs
Area of eden park = Pi*r^2 = 14*14*22/7 = 44*14 = 616 sq mtrs

Is this solution Helpfull? Yes | No   

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