Latest self Aptitude Question SOLUTION: A six-digit number is formed using all the Six digits 2, 3, 4, 5, 7,8.what is the probability that it is divisible by 11?

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(#M40013740) SELF question Keep an EYE

A six-digit number is formed using all the Six digits 2, 3, 4, 5, 7,8.what is the probability that it is divisible by 11?

Amit kumar (11 years ago)

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Amit kumar  (11 years ago)

If p is the Sum of the digits in the odd places and q is the Sum of the digits in the even places.
p+q = 29
p-q = ±11
=> (p,q)= (9,20)(20,9)
=> m= 2+3+4 and n= 5+7+8,
the number of numbers divisible by 11 is 2(3!)^2= 72
the total number of numbers = 6!
probability = 72/(6!)= 1/10

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ANKIT CHAUDHARY  (11 years ago)

1/120 total numbers made by 2,3,4,5,7,8 are 720 and total numbers that are divisible by 11 are 6

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