Latest exam Aptitude Question SOLUTION: I need to solve the equation cos^2(theta) = 4sin(theta)+4, on the interval 0<(theta)<2pi. I thought I had simplified it correctly using trig identities, but something went w

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I need to solve the equation cos^2(theta) = 4sin(theta)+4, on the interval 0<(theta)<2pi. I thought I had simplified it correctly using trig identities, but something went wrong. Thanks!: Asked In exam (9 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Previous Question: PLease help to simplify 4i^7 - the square root of -5 times the square root of -5 + the square root of 7 times the square root of -7 - the square root of -16 Next Question: sqrt4(sqrt32+3sqrt8)

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